1 / 30

CHAPTER 14

CHAPTER 14. Systems of Particles. 14.1. INTRODUCTION. In the current chapter, you will study the motion of systems of particles.

joelle
Download Presentation

CHAPTER 14

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. CHAPTER 14 Systems of Particles

  2. 14.1. INTRODUCTION • In the current chapter, you will study the motion of systems of particles. • The effective force of a particle is defined as the product of it mass and acceleration. It will be shown that the system of external forces acting on a system of particles is equipollent with the system of effective forces of the system. • The mass center of a system of particles will be defined and its motion described. • Application of the work-energy principle and the impulse-momentum principle to a system of particles will be described. Results obtained are also applicable to a system of rigidly connected particles, i.e., a rigid body. • Analysis methods will be presented for variable systems of particles, i.e., systems in which the particles included in the system change.

  3. 14.2. APPLICATION OF NEWTON’S LAWS TO THE MOTION OF A SYSTEM OF PARTICLES. EFFECTIVE FORCES • Newton’s second law for each particle Pi in a system of n particles, • The system of external and internal forces on a particle is equivalent to the effective force of the particle. • The system of external and internal forces acting on the entire system of particles is equivalent to the system of effective forces.

  4. Summing over all the elements, • Since the internal forces occur in equal and opposite collinear pairs, the resultant force and couple due to the internal forces are zero, • The system of external forces and the system of effective forces are equipollent by not equivalent.

  5. 14.3. LINEAR AND ANGULAR MOMENTUM OF A SYSTEM OF PARTICLES • Linear momentum of the system of particles, • Angular momentum about fixed point O of system of particles, • Resultant of the external forces is equal to rate of change of linear momentum of the system of particles, • Moment resultant about fixed point O of the external forces is equal to the rate of change of angular momentum of the system of particles,

  6. 14.4. MOTION OF THE MASS CENTER OF A SYSTEM OF PARTICLES • Mass center Gof system of particles is defined by position vector which satisfies • Differentiating twice, • The mass center moves as if the entire mass and all of the external forces were concentrated at that point.

  7. 14.5. ANGULAR MOMENTUM OF A SYSTEM OF PARTICLES ABOUT ITS MASS CENTER • The angular momentum of the system of particles about the mass center, • Consider the centroidal frame of reference Gx’y’z’,which translates with respect to the Newtonian frame Oxyz. • The moment resultant about G of the external forces is equal to the rate of change of angular momentum about G of the system of particles. • The centroidal frame is not, in general, a Newtonian frame.

  8. Angular momentum about Gof particles in their absolute motion relative to the Newtonian Oxyz frame of reference. • Angular momentum about G of the particles in their motion relative to the centroidal Gx’y’z’,frame of reference, • Angular momentum about G of the particle momenta can be calculated with respect to either the Newtonian or centroidal frames of reference.

  9. 14.6. CONSERVATION OF MOMENTUM FOR A SYSTEM OF PARTICLES • If no external forces act on the particles of a system, then the linear momentum and angular momentum about the fixed point O are conserved. • Concept of conservation of momentum also applies to the analysis of the mass center motion, • In some applications, such as problems involving central forces,

  10. 14.7. KINETIC ENERGY OF A SYSTEM OF PARTICLES • Kinetic energy of a system of particles, • Expressing the velocity in terms of the centroidal reference frame, • Kinetic energy is equal to kinetic energy of mass center plus kinetic energy relative to the centroidal frame.

  11. 14.8. WORK-ENERGY PRINCIPLE. CONSERVATION OF ENERGY FOR A SYSTEM OF PARTICLES • Principle of work and energy can be applied to each particle Pi, where represents the work done by the internal forces and the resultant external force acting on Pi. • Principle of work and energy can be applied to the entire system by adding the kinetic energies of all particles and considering the work done by all external and internal forces. • Although and are equal and opposite, the work of these forces will not, in general, cancel out. • If the forces acting on the particles are conservative, the work is equal to the change in potential energy and which expresses the principle of conservation of energy for the system of particles.

  12. 14.9. PRINCIPLE OF IMPULSE AND MOMENTUM FOR A SYSTEM OF PARTICLES • The momenta of the particles at time t1and the impulse of the forces from t1 to t2 form a system of vectors equipollent to the system of momenta of the particles at time t2 .

  13. 14.10. VARIABLE SYSTEMS OF PARTICLES • Kinetics principles established so far were derived for constant systems of particles, i.e., systems which neither gain nor lose particles. • A large number of physics and engineering applications require the consideration of variable systems of particles, e.g., hydraulic turbine, rocket engine, etc. • For analyses, consider auxiliary systems which consist of the particles instantaneously within the system plus the particles that enter or leave the system during a short time interval. The auxiliary systems, thus defined, are constant systems of particles.

  14. 14.11. STEADY STREAM OF PARTICLES • System consists of a steady stream of particles against a vane or through a duct. • Define auxiliary system which includes particles which flow in and out over D t. • The auxiliary system is a constant system of particles over D t.

  15. Steady Stream of Particles. Applications • Fluid Stream Diverted by Vane or Duct • Fan • Fluid Flowing Through a Pipe • Jet Engine • Helicopter

  16. 14.12. STREAMS GAINING OR LOSING MASS • Define auxiliary system to include particles of mass m within system at time t plus the particles of mass Dm which enter the system over time interval D t. • The auxiliary system is a constant system of particles.

  17. Work Some Example Problems

  18. 14.92 A chain of length l and mass m falls through a small hole in a plate. Initially, when y is very small, the chain is at rest. In each case shown on this slide and a later slide, determine (a) the acceleration of the first link as a function of y and (b) the velocity of the chain as the last link passes through the hole. In this first case assume that the individual links are at rest until they fall through the hole and in the later case assume that at any instant all links have the same speed. Ignore the effect of friction in both cases. Define a mass/length The mass of length y is

  19. Apply the principle of momentum-impulse. Direction is positive downward. Can you see what we can do to simplify this?

  20. Remember that or In general this integrates to Therefore

  21. When y = l WOW

  22. Fory = l

  23. A 1200 lb spacecraft is designed to include a two stage rocket with stages A and B, each weighing 21,300 lb, including 20,000 lb of fuel. The fuel is consumed at a rate of 500 lb/s and ejected with a relative velocity of 12,000 ft/s. Knowing that when stage A expels its last particle of fuel, its casing is released and jettisoned, determine the altitude at which (a) stage A of the rocket is released and (b) the fuel of both stages has been consumed. Velocity of the exhaust Given: Total Weight Time to burn one tank of fuel

  24. Apply the principle of momentum-impulse. Direction is positive upward. There is a corresponding

  25. At t = 40 s This is needed later.

  26. To get the height at the second stage burnout use You would again integrate from t = 0 to t = 40 s and use

More Related