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7.3 Find Measures of Central Tendency and Dispersion

7.3 Find Measures of Central Tendency and Dispersion. p. 259. Vocabulary. Statistics: numerical values used to summarize and compare sets of data Measure of central tendency: number used to represent the center or middle set of data Mean - the average Median – the middle number

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7.3 Find Measures of Central Tendency and Dispersion

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  1. 7.3 Find Measures of Central Tendency and Dispersion p. 259

  2. Vocabulary • Statistics: numerical values used to summarize and compare sets of data • Measure of central tendency: number used to represent the center or middle set of data • Mean - the average • Median – the middle number • Mode – number that occurs most

  3. Vocabulary • Measure of Dispersion: statistic that tells you how spread out the values are • Range – biggest - smallest • Standard Deviation: “sigma”

  4. … 8+ 11+ + 23 144 16 = = = 9 9 198 9 Office B: Mean:x Office A: Mean:x 14 + 17 + + 32 … 22 = = = 9 EXAMPLE 1 Find measures of central tendency Waiting Times The data sets at the right give the waiting times (in minutes) of several people at two veterinary offices. Find the mean, median, and mode of each data set. SOLUTION Median:20Mode:24 Median:18Mode:18

  5. 7.4 = 1. The data set below gives the waiting times (in minutes) of 10 students waiting for a bus. Find the mean, median, and mode of the data set. 4, 8, 12, 15, 3, 2, 6, 9, 8, 7 Mean:x = … 74 4 + 8 + 12 + + 7 = 10 10 for Example 1 GUIDED PRACTICE TRANSPORTATION SOLUTION Median:7.5Mode:8

  6. EXAMPLE 2 Find ranges of data sets Find the range of the waiting times in each data set. Explain what that means. SOLUTION Office A: Range= 32 – 14 = 18 Office B: Range= 23 – 8 = 15 Because the range for office A is greater, its waiting times are more spread out.

  7. EXAMPLE 3 Standardized Test Practice

  8. The correct answer is D. ANSWER 290 5.7 = 9 ... – + + (32 22)2 ... – – (8 16)2+ (11 16)2+ + (23 16)2 – Office B: 182 = 4.5 9 = 9 EXAMPLE 3 Standardized Test Practice – (14 22)2 – + (17 22)2 Office A: = 9

  9. SOLUTION Range= 15 – 2 = 13 Standard deviation = 3.8 for Examples 2 and 3 GUIDED PRACTICE • Find the range and standard deviation of the data set. • 4, 8, 12, 15, 3, 2, 6, 9, 8, 7

  10. Classwork • 2-12 Even • 1-13 Odd, & 18 Homework

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