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Chapter 5 Probability

Chapter 5 Probability. 5.2 Random Variables 5.3 Binomial Distribution 5.4 Mean, Variance, Standard Deviation for Binomial Distribution. Random variable a variable (typically represented by x ) that takes a numerical value by chance.

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Chapter 5 Probability

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  1. Chapter 5Probability 5.2 Random Variables 5.3 Binomial Distribution 5.4 Mean, Variance, Standard Deviation for Binomial Distribution

  2. Random variablea variable (typically represented by x) that takes a numerical value by chance. For each outcome of a procedure, x takes a certain value, but for different outcomes that value may be different. Random Variables

  3. Examples: • Number of boys in a randomly selected family with three children. Possible values: x=0,1,2,3 • The weight of a randomly selected person from a population. Possible values: positive numbers, x>0

  4. Discrete random variableeither a finite number of values or countable number of values (resulting from a counting process) Discrete and Continuous Random Variables • Continuous random variableinfinitely many values, and those values can be associated with measurements on a continuous scale without gaps or interruptions

  5. Probability Distributions • Probability distributiona description that gives the probability for each value of the random variable; often expressed in the format of a table, graph, or formula

  6. Tables Values: Probabilities:

  7. Graphs The probability histogram is very similar to a relative frequency histogram, but the vertical scale shows probabilities.

  8. P(x) = 1 where x assumes all possible values. Requirements for Probability Distribution • 0 P(x) 1 • for every individual value of x.

  9. µ=[x•P(x)]Mean 2=[(x –µ)2 • P(x)] Variance 2=[x2 • P(x)]–µ2Variance (shortcut) =[x2 • P(x)]–µ2Standard Deviation Mean, Variance and Standard Deviation of a Probability Distribution

  10. Round results by carrying one more decimal place than the number of decimal places used for the random variable x. If the values of xare integers, round µ, ,and 2 to one decimal place. Roundoff Rule for µ,,and2

  11. Using StatCrunch (1) Enter the values and their probabilities as separate columns

  12. Using StatCrunch (2) Stat → Calculators → Custom

  13. Using StatCrunch (2) Use var1 for “Values in” and var2 for “Weights in”

  14. Using StatCrunch (4) The distribution, mean, and standard deviation will be displayed

  15. Identifying Unusual Results Range Rule of Thumb According to the range rule of thumb, most values should lie within 2 standard deviations of the mean. We can therefore identify “unusual” values by determining if they lie outside these limits: Maximum usual value = μ + 2σ Minimum usual value = μ – 2σ

  16. Identifying Unusual Results By Probabilities Using Probabilities to Determine When Results Are Unusual: • Unusually high: a particular value x is unusually high if P(xor more) ≤ 0.05. • Unusually low: a particular value x is unusually low if P(xor fewer) ≤ 0.05.

  17. Binomial Probability Distribution A binomial probability distribution results from a procedure that meets all the following requirements: 1. The procedure has a fixed number of trials. 2. The trials must be independent. (The outcome of any individual trial doesn’t affect the probabilities in the other trials.) 3. Each trial must have all outcomes classified into twocategories (commonly referred to as success and failure). 4. The probability of a success remains the same in all trials.

  18. Notation for Binomial Probability Distributions S and F (success and failure) denote the two possible categories of all outcomes; p and q denote the probabilities of S and F, respectively: P(S) = p (p = probability of success) P(F) = 1 – p = q (q = probability of failure)

  19. Notation (continued) n denotes the fixed number of trials. x denotes a specific number of successes in n trials, so x can be any whole number between 0 and n, inclusive. p denotes the probability of success in one of the n trials. q denotes the probability of failure in one of the n trials. P(x) denotes the probability of getting exactly x successes among the n trials.

  20. Methods for Finding Probabilities We will now discuss two methods for finding the probabilities corresponding to the random variable x in a binomial distribution.

  21. n! P(x) = •px•qn-x (n –x)!x! for x = 0, 1, 2, . . ., n Method 1: Using the Binomial Probability Formula where n = number of trials x = number of successes among n trials p = probability of success in any one trial q = probability of failure in any one trial (q = 1 – p)

  22. n! P(x) = •px•qn-x (n –x )!x! The number of outcomes with exactly x successes among n trials Rationale for the Binomial Probability Formula

  23. n! P(x) = •px•qn-x (n –x )!x! The probability of x successes among n trials for any one particular order Number of outcomes with exactly x successes among n trials Binomial Probability Formula

  24. Using StatCrunch (1) Stat → Calculators → Binomial

  25. Using StatCrunch (2) Enter “n” (the sampe size)

  26. Using StatCrunch (3) Enter “p” (the probability of success)

  27. Using StatCrunch (4) Enter “x” (the number of successes)

  28. Using StatCrunch (4) For P(x) use “=“ (probability at x) For ∑P(x) use “<=“ (summed probability)

  29. Example An “unfair coin” has a 0.55 probability of getting heads and is tossed 10 times • What is the probability of getting exactly 5 heads? • What is the probability of getting at least 4 heads?

  30. Probability of heads: p = 0.55 Number of tosses: n = 10 “Exactly 5 heads” → P(5) “at least 4 heads” → ∑P(4) P(5) = 0.234 ∑P(4) = 0.262

  31. Example An “unfair coin” has a 0.55 probability of getting heads and is tossed 10 times p = 0.55 n = 10 • What is the probability of getting exactly 5 heads? • What is the probability of getting at least 4 heads? P(5) = 0.234 ∑P(4) = 0.262

  32. Meanµ = n•p Variance2 = n•p•q Std. Dev. = n • p • q Binomial Distribution: Formulas Where n = number of fixed trials p = probability of success in one of the n trials q = probability of failure in one of the n trials

  33. Maximum usual values = µ + 2 Minimum usual values = µ– 2  Interpretation of Results It is especially important to interpret results. The range rule of thumb suggests that values are unusual if they lie outside of these limits:

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