440 likes | 543 Views
Review 4.6-4.7. Solve each equation or inequality. 1. 2. Multiply every term by 12. b = 2, -5. Solve each equation or inequality. 3. 4. USE QUADRATIC FORMULA. w = 2/5, -1. What values go on your number lines??. 2/5, -1, 0, and 1. Example : Solve. LCM : 2x
E N D
Solve each equation or inequality 1. 2. Multiply every term by 12 b = 2, -5
Solve each equation or inequality 3. 4. USE QUADRATIC FORMULA w = 2/5, -1 What values go on your number lines?? 2/5, -1, 0, and 1
Example: Solve. LCM: 2x Multiply each fraction through by the LCM Check your solution!
Solve. LCM: ? LCM: (x+1) ? Check your solution! No Solution!
Solve. Factor 1st! LCM: (x+2)(x-2) Check your solutions!
Example: Solve. Check your solutions!
Last Example: Solve. Check your solutions!
Solve Check your solution. The LCD for the three denominators is Original equation Multiply each sideby 24(3 – x). Example 6-1a
6 1 1 1 1 1 Simplify. Simplify. Add. Example 6-1b
Check Original equation Simplify. Simplify. Example 6-1c The solution is correct.
Answer: The solution is –45. Example 6-1d
Solve Answer: Example 6-1e
Solve Check your solution. The LCD is Original equation p – 1 1 Multiply by the LCD, (p2 – 1). 1 1 Example 6-2a
DistributiveProperty Simplify. Simplify. Add(2p2 – 2p + 1)toeach side. Example 6-2b
Divide eachside by 3. Factor. Zero ProductProperty or Solve eachequation. Example 6-2c
Check Original equation Simplify. Simplify. Example 6-2d
Original equation Simplify. Example 6-2e Since p = –1 results in a zero in the denominator, eliminate –1. Answer: The solution is p = 2.
Solve Answer: Example 6-2f
Solve Related equation Example 6-5a Step 1 Values that make the denominator equal to 0 are excluded from the denominator.For this inequality the excluded value is 0. Step 2 Solve the related equation.
Multiply each side by 9s. Simplify. Add. Divide each side by 6. Example 6-5b
Step 3 Draw vertical lines at the excluded value and at the solution to separate the number line into regions. Example 6-5c Now test a sample value in each region to determine if the values in the region satisfy the inequality.
Test is a solution. Example 6-5d
Test is not a solution. Example 6-5e
Test is a solution. Example 6-5f
Answer: The solution Example 6-5g
Solve Answer: Example 6-5h
Solve each equation or inequality 6. 7. x = 7 No real solution
Solve each equation or inequality 8. 9. k = 7 m = -13
Solve each equation or inequality 10. t > 14
11.) Find the upper and lower bound of the zeros of: Upper = 4 Lower = -1
Approximate the real zeros of each functions 12. 13. Between 1 and 2 Between -1 and 0 Between 2 and 3
Approximate the real zeros of each functions 14. 15. Between -5 and -4, -1 and 0, 1 and 2 No real zeros
16.) Find the number of positive, negative, and imaginary: Pos. 2 or 0 Neg. 1
Find the remainder of each division. Then state whether the binomial is a factor? 18. 19. Remainder = 55 Not a factor Remainder = 18 Not a factor
27.) Find the discriminant of the function given and describe the nature of the roots. Discriminant = 73 2 distinct real roots
Write the polynomial equation of least degree have the roots: 28.)1, -1, 0.5
Find the roots of each equation: 29. 30.