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CE 3 0 2 Micropocessors Lecture 3

CE 3 0 2 Micropocessors Lecture 3. Levent Eren Izmir University of Economics. Outline. Memory Examples Logic instructions Shifting instructions Arithmetic operations Overflow and carries Important flags setting.

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CE 3 0 2 Micropocessors Lecture 3

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  1. CE302MicropocessorsLecture 3 Levent Eren Izmir University of Economics

  2. Outline • Memory Examples • Logic instructions • Shifting instructions • Arithmetic operations • Overflow and carries • Important flags setting CE302

  3. myvar1 DW 01234h ; define word variable ; (value=1234h) myvar2 DW 01234 ; define word variable ;(value=1234d = 4D2) myvar3 DW ? ; define word variable ;(value uncertain) myvar4 DW 01BCDh ce302msg DB ‘CE302 is great' start: mov ax,cs ; set up data segment mov ds,ax ; DS=CS ; any memory reference we make is assumed to reside in ;the DS segment mov ax,myvar2 ; AX <- myvar2 ; == mov ax,[offset myvar2] ; == mov ax,[2] mov si,OFFSET myvar2 ; use SI as a pointer to myvar2 ; (equiv C code: SI=&myvar2 ) mov ax,[si] ; read memory at myvar2 (*(&myvar2)) ; (indirect reference) mov bx,OFFSET ce302msg ; BX is a pointer to a string ; (equiv C code: BX=&ce302msg) dec BYTE PTR [bx+1] ; make that ‘E' a ‘D' !!!! mov si, 1 ; Use SI as an index inc ce302msg[SI] ; == inc [SI + offset ce302msg] ; == inc [SI + 8] ; == inc [9] Memory Access Example CE302

  4. ;Memory can be addressed using four registers: ; SI -> Assumes DS ; DI -> Assumes DS ; BX -> Assumes DS ; BP -> Assumes SS !!! (this is why it isn't frequently used) ; Examples: mov ax,[bx] ; ax <- word in memory pointed to by BX mov al,[bx] ; al <- byte in memory pointed to by BX mov ax,[si] ; ax <- word pointed to by SI mov ah,[si] ; ah <- byte pointed to by SI mov cx,[di] ; di <- word pointed to by DI mov ax,[bp] ; AX <- SS:[BP] STACK OPERATION!!!! ; In addition, BX+SI and BX+DI are allowed: mov ax,[bx+si] mov ch,[bx+di] ; Furthermore, a fixed 8-bit or 16-bit displacement from the index and base registers is allowed. mov ax,[23h] ; ax <- word in memory DS:0023 mov ah,[bx+5] ; ah <- byte in memory DS:(BX+5) mov ax,[bx+si+107] ; ax <- word at DS:(BX+SI+107) mov ax,[bx+di+47] ; ax <- word at DS:(BX+DI+47) ; REMEMBER: memory to memory moves are ILLEGAL!!! mov [bx],[si] ;ILLEGAL mov [di],[si] ;ILLEGAL (use movsw) ; Special case: stack operations! pop myvar ; myvar <- SS:[SP] Memory Access Example (cont.) CE302

  5. AC (Alignment check) (VM) Virtual mode (RF) Resume (NT) Nested task (IOPL) Input/output privilege level (O) Overflow (D) Direction (I) Interrupt (T) Trace (S) Sign (Z) Zero (A) Auxiliary Carry (P) Parity (C) Carry Flag Register 8086, 8088, 80186 80386, 80486DX 80286 80486SX CE302

  6. Logic Instructions • Logic instructions operate on a bit-by-bit basis NOT: A =~A AND: A &= B OR: A |= B XOR: A ^= B • Except for NOT, these instructions affect the flags as follows: • clear the carry (C) • clear the overflow (O) • set the zero flag (Z) if the result is zero, or clear it otherwise • copy the high order bit of the result into the sign flag (S) • set the parity bit (P) according to the parity (number of 1s) in the result • scramble the auxiliary carry flag (A) • The NOT instruction does not affect any flag CE302

  7. Logic Instructions (cont.) • TEST (non-destructive AND) - logically ANDs two operands and sets the flags but does not save the result • typically one would use this instruction to see if a bit contains one e.g., test al, 1 • sets the flags identically to the AND instruction • AND and OR instructions are often used to mask out data • a mask value is used to force certain bits to zero or one within some other value • a mask typically affects certain bits and leaves other bits unaffected • AND forces selected bits to zero AND cl, 0DFh • OR forces selected bits to one OR cl, 0DFh CE302

  8. Shifting Instructions CE302

  9. Shifting Instructions (cont.) • SHL/SAL (shift left/shift arithmetic left) • moves each bit of the operand one bit position to the left the number of times specified by the count operand • zeros fill vacated positions at the L.O. bit; the H.O. bit shifts into the carry flag • A quick way to multiply by two • Useful in packing data, e.g., consider two nibbles in AL and AH that we want to combine SHL AH, 4 ;requires 80286 or later OR AL, AH NOTE:There are two forms of shifts 1) immediate shift count (8086, 8088 allow an immediate shift of 1 only, e.g., SHL AX, 1)2) CLregister to hold the shift count (e.g., SHL AX, CL) CE302

  10. Example ;multiply AX by decimal 10 (1010) (Same as AX times 2+8 – associate prop) SHL AX, 1 ;AX times 2 MOV BX, AX SHL AX, 2 ;AX times 8 ADD AX, BX ;10 x AX ;multiply AX by 18 (10010) SHL AX, 1 ;AX times 2 MOV BX, AX SHL AX, 3 ;AX times 16 ADD AX, BX ;18 x AX CE302

  11. Shifting Instructions (cont.) • SHR (shift right) • shifts all the bits in the destination operand to the right one bit • zeros fill vacated positions at the H.O. bit • the L.O. bit shifts into the carry flag • A quick way to divide by two (works for unsigned numbers) • Useful for unpacking data, e.g., suppose you want to extract the two nibbles in the AL register, leaving the H.O. nibble in AH and the L.O. nibble in AL: MOV AH, AL ;get a copy of the H.O. nibble SHR AH, 4 ;move H.O. to L.O. and clear H.O. AND AL, 0Fh ;remove H.O. nibble from AL CE302

  12. Shifting Instructions (cont.) • SAR (shift arithmetic right) • shifts all the bits in the destination operand to the right one bit replicating the H.O. bit • the L.O. bit shifts into the carry flag • Main purpose is to perform a signed division by some power of two MOV AX, -15 SAR AX, 1 ; Result is -8 • In 80286 and later you can use SAR to sign extend one register into another, e.g., MOV AH, AL SAR AH, 8 If AL contains 11110001 then AH will contain sign bits extension 1111111111110001 CE302

  13. Shifting Instructions (cont.) • RCL (rotate through carry left) • rotates bits to the left, through the carry flag • bit in the carry flag is written back into bit zero (on the right) • ROL (rotate left) • rotates bits to the left • shifts operand’s H.O. bit into bit zero • e.g., extract bit 10 to 14 in AX and leave these bits in 0 to 4 ROL AX, 6 AND AX, 1Fh NOTE:There are two forms of rotate 1) use of immediate rotate count (8086, 8088 allow an immediate rotate of 1 only, e.g., ROL AX, 1)2) use of registerCL to hold the rotate count CE302

  14. Shifting Instructions (cont.) • RCR (rotate through carry right) • rotates bits to the right, through the carry flag • bit in the carry flag is written back into H.O. bit (on the left) • ROR (rotate right) • rotates bits to rights • shifts operand’s L.O. bit into bit zero CE302

  15. Shifting OperationsExample mov ax,3 ; Initial register values mov bx,5 or ax,9 ; ax <- ax | 00001001 (bitwise OR) and ax,10101010b ; ax <- ax & 10101010 (bitwise AND) xor ax,0FFh ; ax <- ax ^ 11111111 (bitwise XOR) neg ax ; ax <- (-ax) (2's complement) not ax ; ax <- (~ax) (bitwise inversion) shl ax,1 ; logical shift left by 1 bit shr ax,1 ; logical shift right by 1 bit rol ax,1 ; rotate left (LSB=MSB) ror ax,1 ; rotate right (MSB=LSB) mov cl,3 ; Use CL to shift 3 bits shr ax,cl ; Divide AX by 8 shl bx,cl ; Multiply BX by 8 CE302

  16. Simple Arithmetic Instructions • ADD (addition): A += B • Register addition, e.g., ADD AX, BX • Immediate addition, e.g., ADD DL, 33h • Memory to register addition, e.g., memory data added to AL: MOV DI, OFFSET NUMB ;address NUMB MOV AL, 0 ;clear sum ADD AL, [DI] ;add NUMB ADD AL, [DI + 1] ;add NUMB + 1 • NOTE: any ADD instruction modifies the contents of the sign, zero, carry, auxiliary carry, parity, and overflow flags CE302

  17. Simple Arithmetic Instructions (cont.) • INC (increment addition): A++, e.g., memory data added to AL: MOV DI, OFFSET NUMB ;address NUMB MOV AL, 0 ;clear sum ADD AL, [DI] ;add NUMB INC DI ADD AL, [DI] ;add NUMB + 1 NOTE: The increment instructions do not affect the carry flag bit. CE302

  18. Simple Arithmetic Instructions (cont.) • ADC (addition with carry) - functions as regular addition, except the bit in the carry flag (C) is also added to the result • used mainly to add numbers that are wider than 16 bits (8086 - 80286) or wider than 32 bits in the 80386, 80486) • Example: • addition of two 32-bit numbers (BX:AX) + (DX:CX): ADD AX, CX ADC BX, DX CE302

  19. Simple Arithmetic Instructions (cont.) • SUB (subtraction): A -= B • Register subtraction, e.g., SUB CL, BL • Immediate subtraction, e.g., MOV CH, 22h SUB CH, 44h • NOTE: any SUB instruction modifies the contents of the sign, zero, carry, auxiliary carry, parity, and overflow flags Result is -34 (1101 1110) Flags change: Z = 0 (result not zero) C = 1 (borrow) A = 1 (half-borrow) S = 1 (result negative) P = 1 (even parity) 0 = 0 (no overflow) CE302

  20. Simple Arithmetic Instructions (cont.) • DEC (decrement subtraction): A--, subtracts a 1 from a register or the contents of a memory location e.g., DEC BH NOTE:The increment instructions do not affect the carry flag bit. • SBB (subtract with borrow) functions as regular subtraction, except the carry flag (C), which holds the borrow, also subtracts from the difference • used mainly to subtract numbers that are wider than 16 bits (8086 - 80286) or wider than 32 bits in the 80386, 80486) • Example: • subtraction of two 32-bit numbers (BX:AX) - (SI:DI): SUB AX, DI SBB BX, SI CE302

  21. Overflow and Carries • Carry • indicates a carry after addition or a borrow after subtraction • CF: carry flag (unsigned) {1 = CY (there is carry); 0 = NC (no carry)} • e.g., 36,864 (9000h) + 36,864 (9000h) = 73,728 (12000h) > 65,535 (FFFFh) {OV, CY} • carry is set when unsigned goes out of range (denotes an unsigned arithmetic overflow) • Overflow • condition that occurs when signed numbers are added or subtracted • OF: overflow flag (signed) {1 = OV, 0 = NV} • e.g., 20,480 (5000h) + 20,480 (5000h) = 40,960 (A000h) > 32,767 (7FFFh) {OV, NC} • overflow is set when signed goes out of range (denotes a signed arithmetic overflow) • Example: FFFFh + FFFFh = FFFEh {(-1) + (-1)} = -2; NV, CY CE302

  22. Overflows & Carries Example MOV AX, 19 ADD AX, 7 ; AX <- AX + 7 = 26 NEG AX ; AX <- -AX = -26 = 0FFE6h MOV AX,0FFFEh ; 65534 ; Unsigned ADD AX,3 ; MOV AX,0FFFEh ; -2 ; Signed ADD AX,3 ; ; CPU sets flags for both cases (signed and unsigned) MOV BX,6 SUB BX,7 INC BX CE302

  23. Flag Settings FLAG Name Description Notes ZF Zero 1:ZR:Zero 1 indicates that the result was zero 0:NZ: Non-zero CF Carry 1:CY Unsigned Math and shifting 0:NC Needed a carry or borrow OF Overflow 1:OV Signed Math 0:NV Also (+) or (-) to be represented as a valid two’s complement number SF Sign Flag 1:NG: - MSB of result 0:PL: + CE302

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