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2-9

2-9. Absolute–Value Functions. Warm Up. Lesson Presentation. Lesson Quiz. Holt McDougal Algebra 2. Holt Algebra 2. 5. f ( x ) = x + 2; vertical stretch by a factor of 4. Warm Up Evaluate each expression for f (4) and f (-3). 1. f ( x ) = –| x + 1|. –5; –2.

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2-9

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  1. 2-9 Absolute–Value Functions Warm Up Lesson Presentation Lesson Quiz Holt McDougal Algebra 2 Holt Algebra 2

  2. 5.f(x) = x + 2; vertical stretch by a factor of 4 Warm Up Evaluate each expression for f(4) and f(-3). 1.f(x) = –|x + 1| –5; –2 2.f(x) = 2|x| – 1 7; 5 3.f(x) = |x + 1| + 2 7; 4 Let g(x) be the indicated transformation of f(x). Write the rule for g(x). 4. f(x) = –2x + 5; vertical translation 6 units down g(x) = –2x– 1 g(x) = 2x + 8

  3. Objective Graph and transform absolute-value functions.

  4. Vocabulary absolute-value function

  5. An absolute-value function is a function whose rule contains an absolute-value expression. The graph of the parent absolute-value function f(x) = |x| has a V shape with a minimum point or vertex at (0, 0).

  6. The absolute-value parent function is composed of two linear pieces, one with a slope of –1 and one with a slope of 1. In Lesson 2-6, you transformed linear functions. You can also transform absolute-value functions.

  7. Remember! The general forms for translations are Vertical: g(x) = f(x) + k Horizontal: g(x) = f(x– h)

  8. Example 1A: Translating Absolute-Value Functions Perform the transformation on f(x) = |x|. Then graph the transformed function g(x). 5 units down f(x) = |x| g(x) = f(x) + k g(x) = |x| – 5 Substitute. The graph of g(x) = |x| – 5 is the graph of f(x) = |x| after a vertical shift of 5 units down. The vertex of g(x) is (0, –5).

  9. Example 1A Continued The graph of g(x) = |x|– 5 is the graph of f(x) = |x| after a vertical shift of 5 units down. The vertex of g(x) is (0, –5). f(x) g(x)

  10. Example 1B: Translating Absolute-Value Functions Perform the transformation on f(x) = |x|. Then graph the transformed function g(x). 1 unit left f(x) = |x| g(x) = f(x– h) g(x) = |x – (–1)| = |x + 1| Substitute.

  11. Example 1B Continued The graph of g(x) = |x + 1| is the graph of f(x) = |x| after a horizontal shift of 1 unit left. The vertex of g(x) is (–1, 0). f(x) g(x)

  12. Check It Out! Example 1a Let g(x) be the indicated transformation of f(x) = |x|. Write the rule for g(x) and graph the function. 4 units down f(x) = |x| g(x) = f(x) + k g(x) = |x| – 4 Substitute.

  13. Check It Out! Example 1a Continued The graph of g(x) = |x| – 4 is the graph of f(x) = |x| after a vertical shift of 4 units down. The vertex of g(x) is (0, –4). f(x) g(x)

  14. Check It Out! Example 1b Perform the transformation on f(x) = |x|. Then graph the transformed function g(x). 2 units right f(x) = |x| g(x) = f(x– h) g(x) = |x – 2| = |x –2| Substitute.

  15. Check It Out! Example 1b Continued The graph of g(x) = |x – 2| is the graph of f(x) = |x| after a horizontal shift of 2 units right. The vertex of g(x) is (2, 0). f(x) g(x)

  16. Because the entire graph moves when shifted, the shift from f(x) = |x| determines the vertex of an absolute-value graph.

  17. Example 2: Translations of an Absolute-Value Function Translate f(x) = |x|so that the vertex is at (–1, –3). Then graph. g(x) = |x – h| + k g(x) = |x – (–1)| + (–3) Substitute. g(x) = |x + 1| – 3

  18. Example 2 Continued The graph of g(x) = |x + 1| – 3 is the graph of f(x) = |x| after a vertical shift down 3 units and a horizontal shift left 1 unit. f(x) The graph confirms that the vertex is (–1, –3). g(x)

  19. Check It Out! Example 2 Translate f(x) = |x| so that the vertex is at (4, –2). Then graph. g(x) = |x –h| + k g(x) = |x – 4| + (–2) Substitute. g(x) = |x –4| – 2

  20. f(x) g(x) Check It Out! Example 2 Continued The graph of g(x) = |x – 4| – 2 is the graph of f(x) = |x| after a vertical down shift 2 units and a horizontal shift right 4 units. The graph confirms that the vertex is (4, –2).

  21. Remember! Remember! Reflection across x-axis: g(x) = –f(x) Reflection across y-axis: g(x) = f(–x) Vertical stretch and compression : g(x) = af(x) Horizontal stretch and compression: g(x) = f Absolute-value functions can also be stretched, compressed, and reflected.

  22. Example 3A: Transforming Absolute-Value Functions Perform the transformation. Then graph. Reflect the graph. f(x) =|x –2| + 3 across the y-axis. g(x) = f(–x) Take the opposite of the input value. g(x) = |(–x) – 2| + 3

  23. g f Example 3A Continued The vertex of the graph g(x) = |–x – 2| + 3 is (–2, 3).

  24. Example 3B: Transforming Absolute-Value Functions Stretch the graph. f(x) = |x| – 1 vertically by a factor of 2. g(x) = af(x) g(x) = 2(|x| – 1) Multiply the entire function by 2. g(x) = 2|x| – 2

  25. f(x) g(x) Example 3B Continued The graph of g(x) = 2|x| – 2 is the graph of f(x) = |x| – 1 after a vertical stretch by a factor of 2. The vertex of g is at (0, –2).

  26. Substitute for b. Example 3C: Transforming Absolute-Value Functions Compress the graph of f(x) = |x + 2| – 1 horizontally by a factor of . g(x) = |2x + 2| – 1 Simplify.

  27. g Example 3C Continued The graph of g(x) = |2x + 2|– 1 is the graph of f(x) = |x + 2| – 1 after a horizontal compression by a factor of . The vertex of g is at (–1, –1). f

  28. Check It Out! Example 3a Perform the transformation. Then graph. Reflect the graph. f(x) = –|x – 4| + 3 across the y-axis. g(x) = f(–x) Take the opposite of the input value. g(x) = –|(–x) – 4| + 3 g(x) = –|–x – 4| + 3

  29. Check It Out! Example 3a Continued The vertex of the graph g(x) = –|–x – 4| + 3 is (–4, 3). g f

  30. g(x) = (|x| + 1) Multiply the entire function by . g(x) = (|x| + ) Check It Out! Example 3b Compress the graph of f(x) = |x| + 1 vertically by a factor of . g(x) = a(|x| + 1) Simplify.

  31. The graph of g(x) = |x| + is the graph of g(x) = |x| + 1 after a vertical compression by a factor of . The vertex of g is at ( 0, ). Check It Out! Example 3b Continued f(x) g(x)

  32. g(x) = f( x) g(x) = | (4x)| – 3 Check It Out! Example 3c Stretch the graph. f(x) = |4x| – 3 horizontally by a factor of 2. Substitute 2 for b. Simplify. g(x) = |2x| – 3

  33. g f Check It Out! Example 3c Continued The graph of g(x) = |2x| – 3 the graph of f(x) = |4x| – 3 after a horizontal stretch by a factor of 2. The vertex of g is at (0, –3).

  34. f g Lesson Quiz: Part I Perform each transformation. Then graph. 1. Translate f(x) = |x| 3 units right. g(x)=|x – 3|

  35. f g Lesson Quiz: Part II Perform each transformation. Then graph. 2. Translate f(x) = |x| so the vertex is at (2, –1). Then graph. g(x)=|x – 2| – 1

  36. Lesson Quiz: Part III Perform each transformation. Then graph. 3. Stretch the graph of f(x) = |2x| – 1 vertically by a factor of 3 and reflect it across the x-axis. g(x)= –3|2x| + 3

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