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Explore solutions concentrations, molarity calculations, and volume adjustments in chemistry problems. Practice with various scenarios and concepts to enhance understanding.
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Clicker #1 • Which of the three solutions is the most concentrated? A) Solution #1 B) Solution #2 C) Solution #3 D) The concentrations are the same.
Clicker #2 You add 300.0 mL of water to 300.0 mL of a 2.00 M sugar solution. How many of the following will change? I. total volume of the solution II. moles of solute in the solution III. mass of solute in the solution IV. concentration of the solution V. number of solute molecules in the solution A) 1 B) 2 C) 3 D) 4 E) 5
Solution Problem #1 • You have 1.00 mol of sugar in 125.0 mL of solution. Calculate the concentration in units of molarity.
Solution Problem #2 • You have a 2.50 M sugar solution. Calculate the number of moles of sugar in 300.0 mL of this solution.
Solution Problem #3 • You have a 10.0 M sugar solution. What volume of this solution do you need to have 2.00 mol of sugar?
Clicker #3 If 200. mL is removed from the original 10.0 M solution, what is the concentration of the remaining (original) solution? A) 0.100 M B) 1.00 M C) 2.00 M D) 8.00 M E) 10.0 M
Solution Problem #4 • You add 250.0 mL of water to 250.0 mL of a 4.00 M sugar solution. Calculate the concentration of the new solution in units of molarity. (Assume the volumes are additive.)
Clicker #4 Do you predict that the concentration of the 4.00 M sugar solution will increase, decrease, or stay the same? A) increase B) decrease C) stay the same
Solution Problem #5 • Consider separate solutions of NaOH and KCl made by dissolving equal masses of each solute in equal volumes of solution. Which solution has the greater concentration?
Clicker #5 Without using a calculator, which solution has the greater concentration? MM of NaOH = 39.99 g/mol MM of KCl = 74.55 g/mol A) NaOH B) KCl
Solution Problem #6 • Consider separate solutions of NaOH and KCl made by dissolving 100.0 g of each solute in 250.0 mL of solution. Calculate the concentration of each solution.
Solution Problem #7 • We have a 0.800 M solution of NaOH. You need 75.0 mL of a 0.35 M solution. How do you make such a solution?
Solution Problem #8 • You prepare 525 mL of a 0.50 M solution of HI in an Erlenmeyer flask. You forget to seal the flask and don’t realize this until you find it three days later. Checking its molarity, you now find it to be a 0.82 M solution. How much water evaporated?
Solution Problem #9 • Answer the following questions for 60.0 mL of 2.00 M calcium chloride solution. a) How many moles of calcium chloride are in solution? How many moles of chloride ions are in this same solution? b) You add 40.0 mL of water to the solution. How many moles of calcium chloride are in the new solution? c) What is the molarity of the new solution?
Solution Problem #10 • I mix 220 mL of 1.5 M HCl solution with 405 mL of 0.42 M HCl solution. Indicate the volume and molarity of the final solution.