1 / 8

Double Cheeseburgers and Stoichiometry

Double Cheeseburgers and Stoichiometry. 1 Double Cheeseburger needs 1 bun, 2 patties, 2 slices of cheese, 4 strips of bacon For 5 Double Cheeseburgers how many units of each ingredient do I need? Fill in the final column below with how many complete burgers I can make:. Objectives.

julietten
Download Presentation

Double Cheeseburgers and Stoichiometry

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Double Cheeseburgers and Stoichiometry • 1 Double Cheeseburger needs 1 bun, 2 patties, 2 slices of cheese, 4 strips of bacon • For 5 Double Cheeseburgers how many units of each ingredient do I need? • Fill in the final column below with how many complete burgers I can make:

  2. Objectives • To understand the concept of limiting reactants • To learn to recognize the limiting reactant in a reaction • To learn to use the limiting reactant to do stoichiometric calculations • To learn to calculate percent yield

  3. A. The Concept of Limiting Reactants • Stoichiometric mixture • N2(g) + 3H2(g) 2NH3(g)

  4. A. The Concept of Limiting Reactants • Limiting reactant mixture • N2(g) + 3H2(g) 2NH3(g)

  5. A. The Concept of Limiting Reactants • For a Limiting reactant mixture the number of moles are not balanced to match the reaction equation • N2(g) + 3H2(g) 2NH3(g) • Limiting reactant is the reactant that runs out first • When the limiting reactant is exhausted, then the reaction stops

  6. B. Calculations Involving a Limiting Reactant

  7. Method 1: LAURA CHANG METHOD OF LR DETERMINATION • Grams of reactant A- convert to moles and divide by the coefficient g/(g/mol)= x/coeff • Grams of reactant B- convert to moles and divide by the coefficient (g/(g/mol)= x/coeff) The smaller value is the limiting reactant!

  8. Method 2:Calculations Involving a Limiting Reactant

More Related