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Molar Conversions

MASS IN GRAMS. MOLES. NUMBER OF PARTICLES. Molar Conversions. molar mass. 6.02  10 23. ( g/mol ). ( particles/mol ). EXAMPLE: GRAMS TO MOLES. How many moles of carbon are in 26 g of carbon?. 26 g C. 1 mol C 12.01 g C. = 2.16 mol C. SOLVE: GRAMS TO MOLES.

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Molar Conversions

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  1. MASS IN GRAMS MOLES NUMBER OF PARTICLES Molar Conversions molar mass 6.02  1023 (g/mol) (particles/mol)

  2. EXAMPLE: GRAMS TO MOLES • How many moles of carbon are in 26 g of carbon? 26 g C 1 mol C 12.01 g C = 2.16 mol C

  3. SOLVE: GRAMS TO MOLES • How many moles of phosphorus are in 84 g of phosphorus? 84 g P = ___ mol P

  4. EXAMPLE: MOLES TO GRAMS • How many grams of carbon are in 2.2 moles of carbon? 2.2 mol C 12.01 g C 1 mole C = 26.42 g C

  5. SOLVE: MOLES TO GRAMS • How many grams of water (H2O) are in 4.2 moles of water? 4.2 mol H2O = _____ g H2O HINT! 1 mol of H2O = molar mass of H2O

  6. EXAMPLE: MOLES TO MOLECULES • How many molecules are in 2.50 moles of C12H22O11? 6.02  1023 molecules 1 mol 2.50 mol = 1.51  1024 molecules C12H22O11

  7. SOLVE: MOLES TO MOLECULES • How many molecules are in 3 moles of CO2? 3 mol CO2 = molecules CO2

  8. EXAMPLE: MOLECULES TO MOLES • How many moles are in 4.22 x 1027 molecules of MgO? 1 mol 6.02  1023 Molecules of MgO 4.22 x 1027 molecules of MgO = 7010 moles of MgO

  9. SOLVE: MOLECULES TO MOLES • How many moles are in 1.2 x 1028 molecules of C12H22O11? 1.2 x 1028 molecules of C12H22O11 = moles C12H22O11

  10. EXAMPLE: PARTICLES TO MASS • Find the mass of 2.1  1024 molecules of NaHCO3. 2.1  1024 molecules 1 mol 6.02  1023 molecules 84.01 g 1 mol = 290 g NaHCO3

  11. SOLVE: PARTICLES TO MASS • Find the mass of 5.22 x 1024 molecules of Zinc. 5.22  1024 molecules = g Zn

  12. EXAMPLE: MASS TO PARTICLES • Find the number of particles present with 3.6 g of K. 3.6 g K 6.02  1023 Atoms K 1 mol 39 g K 1 mol = 5.5 x 10 22 atoms K

  13. SOLVE: MASS TO PARTICLES • Find the number of particles present with 50 g of NaBr. 50 g NaBr = atoms NaBr

  14. EXAMPLE: MASS TO ATOMS • Find the number of oxygen atoms present in 16.5g of O2. 16.5 g O2 6.02  1023 Molecules O2 1 mol 32 g O2 2 atoms 1 molecule of O2 1 mol = 6.2 x 10 23 atoms O2

  15. EXAMPLE: MASS TO ATOMS • Find the number of oxygen atoms present in 355 g of NaNO3. 355 g NaNO3 = # of Oatoms

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