1 / 6

NASTASSIA P. & LENA B.

NASTASSIA P. & LENA B. THE QUESTION. How many buildings the size of the CN Tower would a mole of jelly beans fill up?. THE GIVEN. A mole = 6.0221415 × 10^23 mol^-1 Average volume of jelly bean: 0.015m x 0.01m x 0.01m = 0.0000015m^3 Volume of Cone: 1/3 π r^2 h

kaethe
Download Presentation

NASTASSIA P. & LENA B.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. NASTASSIA P. & LENA B.

  2. THE QUESTION • How many buildings the size of the CN Tower would a mole of jelly beans fill up?

  3. THE GIVEN • A mole = 6.0221415 × 10^23 mol^-1 • Average volume of jelly bean: 0.015m x 0.01m x 0.01m = 0.0000015m^3 • Volume of Cone: 1/3 π r^2 h • Radius at the base of the tower = 33.2m • Height of the CN Tower = 553.33m • Main level floor is 256 square feet • Main level height = 7 stories • 1 story = 10 feet • 1 foot = 0.3048 meters • Main level height = 7 x 10 x 0.3048 = 21.336m Height of 553.55m }7 stories } Radius of 33.2m

  4. THE CALCULATIONS Find volume of the “cone” part. Name it Volume C. • Volume of Cone: 1/3 π (33.2m)^2 x (553.33m) • Volume C = around 638 688m^3 Find volume of Sky Pod. Name it Volume P. • Volume of Sky Pod = 21.336m x 256m^2 • Volume P = around 5462m^3 Total volume of CN Tower = Volume C + Volume P • Total volume = 638 688 + 5462 • Total volume = 644 150m^3

  5. THE CALCULATIONS Multiply Avagadro’s consant by volume of jelly bean. Divide it by volume of CN Tower. • # of CN Towers = Avogadro’s constant x volume of jelly bean volume of 1 CN Tower • Number of CN Towers = (6.022 x 10^23)(0.0000015) 644 150 • Number of CN Towers = 1.402313126 x 10^12 = 1 402 313 126 000

  6. THE END Therefore, 1 402 313 126 000 buildings the size of the CN Tower will fill up a mole of jelly beans.

More Related