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CH110 Foundations of GENERAL, ORGANIC, & BIOCHEMISTRY CHEMEKETA COMMUNITY COLLEGE INSTRUCTOR: Dr. Jan Cammack http://newterra.chemeketa.edu/faculty/camj. 1 st Day Stuff. Who are you? Are you in the right place? GOB CTV Introduction Privacy waver Chemeketa Pipeline Course Web Page
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CH110 • Foundations of • GENERAL, ORGANIC, • & BIOCHEMISTRY • CHEMEKETA COMMUNITY COLLEGE • INSTRUCTOR: Dr. Jan Cammack • http://newterra.chemeketa.edu/faculty/camj
1st Day Stuff • Who are you? Are you in the right place? • GOB • CTV Introduction • Privacy waver • Chemeketa Pipeline • Course Web Page • Course Syllabus & requirements • Who am I? • Web CT Quizzes
CH110 Recitation & Lab: Week 1 • Complete the prelab assignment for Lab Experiment 1: Burners & Flames • Homework problems will be due each week at recitation • Chpts 1(&2) problems due Thur
Chapter 1:Measurement • Units of Measurement • Significant Figures • Conversion Calculations • Density
Units of Measurement meter (m) 1 m = 1.09 yd liter (L) 1 L = 1.06 qt gram (g) 1 kg = 2.2 lb
Matter • =The stuff things are made of. • (Air, water, rocks, etc..) • Matter has Mass and takes up space. • =The amount of stuff (in g’s) • (Bowling Ball > Balloon) Weight on earth. =Pull of Gravity on matter.
Mass Vs. Weight How much would you weigh on another planet? http://www.exploratorium.edu/ronh/weight/
Scientific notation • If a number is larger than 1 • Move decimal point X places left to get a number between 1 and 10. 1 2 3 , 0 0 0 , 0 0 0. = 1.23 x 108 • The resulting number is multiplied by 10X.
Scientific notation • If a number is smaller than 1 • Move decimal point X places right to get a number between 1 and 10. 0. 0 0 0 0 0 0 1 2 3 = 1.23 x 10-7 • The resulting number is multiplied by 10-X.
Examples • Write in Scientific Notation: • 25 = • 8931.5 = • 0.000593 = • 0.0000004 = • 3,210. = 2.5 x 10 1 8.9315 x 10 3 5.93 x 10 - 4 4 x 10 - 7 3.210 x 103
Scientific notation 0.0144939 • 1.44939 x 10-2 = On Calculator 1.44939 (-) 2 EE 1.44939 E-2 x 10 Means x 10 Change Sign
Measured & Exact Numbers • Exact Numbers = • from counting or by definition 12 coins per package 12 coins 1 package 1 package 12 coins = 12 coins 1 dozen coins 1 dozen coins 12 coins =
Measured & Exact Numbers • Measured Numbers = • estimated using a tool All measurements contain some uncertainty. • We make errors • Tools have limits
Significant figures Length of object is between 6.7 and 6.8 The next digit would be a guess. If use 6.76 then have error of + 0.01cm
Certain Digits Uncertain Digit Significant figures • Expresses accuracy & precision. • You can’t report numbers better than the method used to measure them. • 6.76 units = 3sig figures
Significant figures • Sig Figs don’t depend on the decimal point. • 255 millimeters • 25.5 centimeters • 2.55 decimeters • 0.255 meters • 0.0255 decameters 3 Sig Figs
Significant figures: Rules for zeros Leading zeros are notsignificant. 0.00421 3 sig figs Leading zero Captive zeros are significant. 4012 4 sig figs Captive zero Trailing zeros behind decimal are significant. 114.20 5 sig figs Trailing zero
Significant figures: Rules for zeros • 32,000 • Are the 0’s significant? • 2 sig figs = • 3 sig figs = • 4 sig figs = • 5 sig figs = 3.2 x 104 3.20 x 104 3.200 x 104 3.2000 x 104 32,000.
Significant figures: Rules for zeros • 1025 km • 2.00 mg • 0.00570 • 520 Four(Captive zeros are significant) Three(trailing zeros behind decimal are significant) Three(only trailing zero behind decimal is significant, leading zeros are not) Two(No decimal, zero assumed insignif)
Rounding Write with 4 Significant Figures: 2.5795035 becomes 2.580 > 5 round up < 5 round down. 1st insignificant digit 34.204221 becomes 34.20
Significant figuresand calculations • An answer can’t have greater significance than the quantities used to produce it. • Example • How fast did you run if you • went 1.0 km in 3.00 minutes? 0.3333333333 speed = 1.0 km 3.00 min = ?
Simplified rules for significant figures • Multiplication & Division Problems: • Do calculations. speed = 1.0 km 3.00 min = 0.333333333 km min • Look at sig figs for each value in calculation. (Constants don’t count.) 3 sig figs 2 sig figs • Report answer with same sig figs as least significant value. = 0.33 km min • Round off as needed.
Simplified rules for significant figures • Addition & Subtraction Problems: • Do calculations. Significant to .1 1.9 + 18.65 20.55 Significant to .01 • Look at least significant place for each value in calculation. • Report answer to least significant place. = 20.6 Significant to .1 • Round off as needed.
Metric prefixes • Changing the prefix alters the size of a unit. • Prefix Symbol Factor (multiple) mega M 106 1,000,000 kilo k 103 1,000 deci d 10-1 0.1 centi c 10-2 0.01 milli m 10-3 0.001 100 1
Conversion of units • Example:Metric Conversion • How many milligrams (mg) are in 5 kilograms (kg)? • Factor label method • Identify your conversions factors. 1 kg = 1 1000 g 1000 mg = 1 1 g 1000 g = 1 1 kg 1 g = 1 1000 mg
Example:Metric Conversion How many milligrams are in 5 kilograms? • Identify what is to the problem. unique 5 kg = mg • Identify how you want the answer to look.
Example:Metric Conversion How many milligrams are in 5 kilograms? • Multiply by conversion factors until units cancel. 5 kg 1 1000 g 1 kg 1000 mg 1 g = mg 5,000,000 • If the words work, the numbers will work.
Example: English-Metric Conversion You have a pen of rats each with an average weight of 0.75 lb. How much rubbing alcohol will it take to kill ½ of the population if the LD50 is 5000. mg/kg ? • Identify your conversions factors. 1 kg Bw = 1 5000 mg Alc 1.0 kg Bw = 1 2.2 lb Bw 5000 mg Alc = 1 1 kg Bw 2.2 lb Bw = 1 1.0 kg Bw
5000. mgAlc 1 kg BW 1.0kgBW 2.2 lbBW Example: English-Metric Conversion You have a pen of rats each with an average weight of 0.75 lb. How much rubbing alcohol will it take to kill ½ of the population if the LD50 is 5000. mg/kg ? Identify what is unique to the problem. 0.75 lbBW = mgAlc 1704.545 1700 mg = 1.7 x 103 Identify how you want the answer to look.
Density Mass Density = Volume • Water 1.0 Urine 1.01 - 1.03 • Air 0.0013 Bone 1.7 - 2.0 • Gold 19.3 Oil 0.8 - 0.9 1cc = 1 cm3 = 1 ml = 1 g water g cm3 g ml At 4 o C or
Density calculation What is the density of 5.00 ml of serum if it has a mass of 5.230 gs? • d =m • V d =5.230 g 5.00 ml • = 1.05 g • ml
Specific gravity density of substance g ml • Specific Gravity = density of reference g ml Reference commonly water at 4oC • Specific Gravity is unitless. • At 4oC, density = specific gravity.
Specific gravity Hydrometer • Commonly used to test sugar in urine. • Float height will be • based on Specific Gravity.
Density as a Conversion A liquid sample with a density of 1.09 g/mL is found to weigh 7.453 grams. What is the volume of the liquid in mLs? • Identify any conversion factors. • What is unique to the problem? 7.453 g 1 ml 1.09 g = ml 6.837614 = 6.84 ml • How should the answer look? 1.09 g 1 ml 1 ml 1.09 g