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Explore the law of cosines for a plane in wind problem and other homework problems in Chapter 4. Understand the different types of forces and their effects on objects in motion. Learn about inertia, Newton's Laws, and the concept of weight. Solve problems involving ropes, pulleys, inclined planes, and friction.
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Ballistic Cart Demo Discuss law of cosines for planeinwindb problem Other HW problems?
Chapter 4 Forces and Mass
does not apply for very tiny objects (< atomic sizes) objects moving near the speed of light Classical Mechanics
If the net force SF exerted on an object is zero the object continues in its original state of motion. That is, if SF = 0, an object at rest remains at rest and an object moving with some velocity continues with the same velocity. Contrast with Aristotle! Newton’s First Law
Usually a push or pull Vector Either contact or field force Forces
Types Strong nuclear force Electromagnetic force Weak nuclear force Gravity Fundamental (Field) Forces
QCD (Quantum chromodynamics) confines quarksby exchaning gluons Nuclear force: binds protons and neutronsby exchanging pions Strong Nuclear Force
Electromagnetic Forces • Opposites attract, like-signs repel • Electric forces bind electrons in atoms • Magnetic forces arise from moving charges
Involves exchange of heavy W or Z particle Responsible for decay of neutrons Weak Nuclear Force
Attractive force between any two bodies Proportional to both masses Inversely proportional to square of distance Gravity
Tendency of an object to continue in its original motion Inertia (Newton’s First Law)
A measure of the resistance of an object to changes in its motion due to a force Scalar SI units are kg Mass
Acceleration is proportional to net force and inversely proportional to mass. Newton’s Second Law
SI unit is Newton (N) US Customary unit is pound (lb) 1 N = 0.225 lb Units of Force
Weight is magnitude of gravitational force mass weight Weight
Mass is an inherent property Weight depends on location Weight vs. Mass
Single isolated force cannot exist For every action there is an equal and opposite reaction Force on “1” due to “2” Newton’s Third Law
Newton’s Third Law cont. • F12 is action force F21 is reaction force • You can switch action <-> reaction • Action & reaction forces act on different objects
Define the OBJECT (free body) • Newton’s Law uses the forces acting ON object • n and Fg act on object • n’ and Fg’ act on other objects
Objects behave as particles ignore rotational motion (for now) Consider only forces acting ON object neglect reaction forces Assumptions for F=ma
Identify object (free body) Label all forces acting on object Resolve forces into x- and y-components, using convenient coordinate system Apply equations, keep track of signs! Problem Solving Strategy
Strings, ropes and Pulleys Gravity Normal forces Friction Springs (later in the book) Mechanical Forces
Force from rope points AWAY from object Magnitude of the force is called tension Tension does not change when going over a pulley (if frictionless) Some Rules for Ropes and Pulleys
Example 4.1 Given that Mlight = 25 kg, find all three tensions T3 = 245.3 N, T1 = 147.4 N, T2 = 195.7 N
Example 4.2 2) Which statements are correct?Assume the objects are static. A) T1 must = T2 B) T2 must = T3 C) T1 must be < Mg D) T1+T2 must be > Mg A) T B) T C) T D) T cos(10o)=0.985 sin(10o)=0.173
Example 4.3 a) Find acceleration b) Find T, the tension above the bowling ball c) Find T3, the tension in the rope between the pails d) Find force ceiling must exert on pulley a) a = g/6 = 1.635 m/s2b) T= 57.2 Nc) T3=24.5 Nd) Fpulley=2T = 114.5 N
Inclined Planes • Choose x along the incline and y perpendicular to incline • Replace force of gravity with its components
Example 4.4 Find the acceleration and the tension a = 4.43 m/s2, T= 53.7 N
M Example 4.5 Find M such that the box slides at constant v M=15.6 kg
Resistive force between object and neighbors or the medium Examples: Sliding a box Air resistance Rolling resistance Forces of Friction
Direction parallel to surface, opposite toother forces Nearly independent of the area of contact The coefficient of friction (µ) depends on the surfaces in contact Sliding Friction
Static Friction, ƒs • ms is coefficient of static friction • n is the normal force f F
Kinetic Friction, ƒk • mk is coefficient of kinetic friction • Friction force opposes F • n is the normal force f F
Example 4.6 The man pushes/pulls with a force of 200 N. Thechild and sled combo has a mass of 30 kg and the coefficient of kinetic friction is 0.15. For each case:What is the frictional force opposing his efforts? What is the acceleration of the child? f=59 N, a=3.80 m/s2 / f=29.1 N, a=4.8 m/s2
Example 4.7 Given m1 = 10 kg and m2 = 5 kg: a) What value of ms would stop the block from sliding? b) If the box is sliding and mk = 0.2, what is the acceleration? c) What is the tension of the rope? a) ms = 0.5 b) a=1.96 m/s2 c) 39.25 N
Example 4.8 What is the minimum ms required to prevent a sled from slipping down a hill of slope 30 degrees? ms = 0.577
Other kinds of friction • Air resistance, F ~ Area v2 • Rolling resistance, F ~ v Terminal velocity:
Equivalent to “Fictitious” gravitational force Accelerating Reference Frames
Eq. of motion in fixed frame F-maf looks like force in new frame, maf acts like fake gravitational force! Fictitious Force: Derivation
Example 4.9 An elevator falls with acceleration a = 8.0 m/s2. If a 200-lb person stood on a bathroom scale during the fall, what would the scale read? 36.9 lbs
Example 4.10 You are calibrating an accelerometer so that you can measure the steady horizontal acceleration of a car by measuring the angle a ball swings backwards. If M = 2.5 kg and the acceleration, a = 3.0 m/s2:a) At what angle does the ball swing backwards? b) What is the tension in the string? q =17 degT= 25.6 N q