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Mixture Word Problems. Today’s Date: 11/16/11. Notes on Handout. Mixture Equation: Amount • % = Total. Not given to you, but expected to know: Water = 0% “Pure” Acid = 100% Remember: Define variable Write equation Solve. Asking for amt of water. Example 1.
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Mixture Word Problems Today’s Date: 11/16/11 Notes on Handout
Mixture Equation: Amount • % = Total Not given to you, but expected to know: Water = 0% “Pure” Acid = 100% Remember: • Define variable • Write equation • Solve
Asking for amt of water Example 1 How many kilograms of water should be mixed with 60 kg of a 30% acid solution to make a 10% solution? Tells you it’s the mix x 0 0 60 30 (60)(30) x + 60 10 10(x + 60) Amt of Water + Amt of Acid = Amt of Mix Multiply Amt ∙ % in each row
Example 1 cont… x 0 0 60 30 (60)(30) x + 60 10 10(x + 60) Get your equation from the last column Total Water + Total Acid = Total Mix 0 + (60)(30) = 10(x + 60) 1800 = 10x + 600 1200 = 10x 120 = x • x is amt of water • 1800 = 10x + 600 • 120 kg of water
Asking for amt of “pure” salt Example 2 How many kilograms of pure salt must be added to 8 kg of a 10% salt solution to obtain a 20% salt solution? Tells you it’s the mix x 100 100x 8 10 (8)(10) x + 8 20 20(x + 8) 100x + (8)(10) = 20(x + 8)
Example 2 cont… 100x + (8)(10) = 20(x + 8) 100x + 80 = 20x + 160 80x + 80 = 160 80x = 80 x = 1 • x is amt of pure salt • 100x + 80 = 20x + 160 • 1 kg of pure salt
Example 3 How many kilograms of a 30% acid solution must be added to 80 kg of a 20% solution to produce a 25% solution? Tells you it’s the mix x 30 30x 80 20 (80)(20) x + 80 25 25(x + 80) 30x + (80)(20) = 25(x + 80)
Example 3 cont… 30x + (80)(20) = 25(x + 80) 30 x + 1600 = 25x + 2000 5x + 1600 = 2000 5x = 400 x = 80 • x is amt of 30% solution • 30x + 1600 = 25x + 2000 • 80 kg of 30% solution
Homework #9 Two Sided Worksheet: Mixture Problems Review Sum/Difference/Complex Fractions Mix Prob #2: Mix Amt = 36 Need to find Milk Amt & Cream Amt How?