1 / 19

12.3 – Conditional Probability

12.3 – Conditional Probability. Given that A and B are dependent events, the conditional probability of an event B , given that event A has already occurred, is P( B | A ) = P( A and B ) P( A ).

karli
Download Presentation

12.3 – Conditional Probability

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 12.3 – Conditional Probability

  2. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A)

  3. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd

  4. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd P(3|odd)

  5. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd P(3|odd) = P(odd and 3)

  6. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd P(3|odd) = P(odd and 3) P(odd)

  7. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd P(3|odd) = P(odd and 3) P(odd)

  8. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd P(3|odd) = P(odd and 3) P(odd) = 1/6

  9. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd P(3|odd) = P(odd and 3) P(odd) = 1/6 1/2

  10. Given that A and B are dependent events, the conditional probability of an event B, given that event A has already occurred, is P(B|A) = P(A and B) P(A) Ex. 1 If a die is rolled, what is the probability that a 3 was rolled given that the number is odd P(3|odd) = P(odd and 3) P(odd) = 1/6 = 1/3 1/2

  11. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug.

  12. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000

  13. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000 P(H|D)

  14. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000 P(H|D) = P(H and D)

  15. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000 P(H|D) = P(H and D) P(D)

  16. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000 P(H|D) = P(H and D) P(D) = 800/4000

  17. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000 P(H|D) = P(H and D) P(D) = 800/4000 2400/4000

  18. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000 P(H|D) = P(H and D) P(D) = 800/4000 = 800/2400 2400/4000

  19. Ex. 2 Find the probability that a test subject stayed healthy, given that he or she used an experimental drug. Total = 4000 P(H|D) = P(H and D) P(D) = 800/4000= 800/2400= 1/3 2400/4000

More Related