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Projectile Motion

Projectile Motion. A projectile is an object moving in two dimensions under the influence of Earth's gravity ; its path is a parabola. Projectile Motion. It can be understood by analyzing the horizontal and vertical motions separately. Projectile Motion.

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Projectile Motion

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  1. Projectile Motion A projectile is an object moving in two dimensions under the influence of Earth's gravity; its path is a parabola.

  2. Projectile Motion It can be understood by analyzing the horizontal and vertical motions separately.

  3. Projectile Motion The speed in the x-direction is constant; in the y-direction the object moves with constant accelerationg. This photograph shows two balls that start to fall at the same time. The one on the right has an initial speed in the x-direction. It can be seen that vertical positions of the two balls are identical at identical times, while the horizontal position of the yellow ball increases linearly.

  4. 3-7 Projectile Motion If an object is launched at an initial angle of θ0 with the horizontal, the analysis is similar except that the initial velocity has a vertical component.

  5. Solving Problems Involving Projectile Motion Projectile motion is motion with constant acceleration in two dimensions, where the acceleration is g and is down.

  6. Solving Problems Involving Projectile Motion • Read the problem carefully, and choose the object(s) you are going to analyze. • Draw a diagram. • Choose an origin and a coordinate system. • Decide on the time interval; this is the same in both directions, and includes only the time the object is moving with constant acceleration g. • Examine the x and y motions separately.

  7. Solving Problems Involving Projectile Motion 6. List known and unknown quantities. Remember that vx never changes, and that vy = 0 at the highest point. 7. Plan how you will proceed. Use the appropriate equations; you may have to combine some of them.

  8. Solving Problems Involving Projectile Motion Example 1: Driving off a cliff. A movie stunt driver on a motorcycle speeds horizontally off a 50.0-m-high cliff. How fast must the motorcycle leave the cliff top to land on level ground below, 90.0 m from the base of the cliff where the cameras are? Ignore air resistance.

  9. Homework question A pool ball leaves a 0.60-meter high table with an initial horizontal velocity of 2.4 m/s. Predict the time required for the pool ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location

  10. solution y = viy•t +0.5•ay•t2 -0.60 m = (0 m/s)•t + 0.5•(-9.8 m/s/s)•t2 -0.60 m = (-4.9 m/s/s)•t2 0.122 s2 = t2 t = 0.350 s (rounded from 0.3499 s) Once the time has been determined, a horizontal equation can be used to determine the horizontal displacement No acceleration horizontally so simple velocity equations can be used D= v (t) x = (2.4 m/s)•(0.3499 s) x = 0.84 m (rounded from 0.8398 m)

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