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GENETIKA DASAR. POKOK BAHASAN 3 Pautan Gen Pindah Silang Pemetaan Kromosom. HUKUM MENDEL I : “ The Law of Segregation of Allelic Genes” atau Hukum Pemisahan Bebas HUKUM MENDEL II : “ The law of Independent Assortment of Genes” a tau Hukum Pengelompokkan Gen secara Bebas.
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POKOK BAHASAN 3 • Pautan Gen • Pindah Silang • Pemetaan Kromosom
HUKUM MENDEL I : “The Law of Segregation of Allelic Genes” atau Hukum Pemisahan Bebas HUKUM MENDEL II : “The law of Independent Assortment of Genes” atau Hukum Pengelompokkan Gen secara Bebas
Pautan Gen (Linkage gene) • Deviation From Independent Assortment Ratios • Pautan/Berangkai/Linkage gene : Peristiwa beberapa gen bukan alel terdapat pada satu kromosom yang sama
Pautan/Berangkai/Linkage gene : • - RANGKAI/PAUTAN SEMPURNA • Gen-gen yang terangkailetaknya amat • berdekatan, maka selama meiosis gen-gen itu • tidak mengalami perubahan letak. Sehingga • gen-gen itu bersama-sama menuju ke gamet • - RANGKAI/PAUTAN TIDAK SEMPURNA • Gen-gen yang terangkai pada satu kromosom • letaknya tidak berdekatan satu sama lainnya, • sehingga gen-gen itu dapat mengalami • perubahan letak yang disebabkan karena ada • penukaran segmen dari kromatid-kromatid pada • sepasang kromosom homolog
Bateson and Punnett crossed a purple, long snapdragon with one that was red and round • The F1 snapdragon was selfed • Observed deviation from a 9:3:3:1 ratio
Because the parental genes seemed to assort together more then they were expected, Bateson and Punnett said they were coupled
Creating a Linkage Hypothesis • Morgan used Drosophila as an experimental organism to prove linkage
Morgan crossed Drosophila red eye, normal wing (pr+pr+ vg+vg+) and purple eye vestigal wing (prpr vgvg) • The F1 flies were test crossed • Observed deviation from the 1:1:1:1 ratio
Proof That Linked Genes Exist • Morgan hypothesized that alleles of two genes close together may not assort indepentently into gametes • Parental arrangements may appear together in gametes
Morgan performed a second cross to prove the hypothesis • He crossed red eye, vestigal wing (pr+pr+ vgvg) and purple eye, normal wing flies (prpr vg+vg+) • The F1 flies were testcrossed
Parent : pr+pr+ vgvg x prpr vg+vg+ (red eye, vestigal wing) (purple eye, normal wing) F1 : pr+pr vgvg+ x testcross
Terms Used in Linkage Analysis Coupling – the F1 configuration where both dominant alleles reside on the same chromosome; also called CIS gen-gen dominan terangkai pada satu kromosom, sedangkan alel-alel resesifnya terangkai pada kromosom homolognya Penulisannya : AB/ab atau AB ab Repulsion - the F1 configuration where one dominant and one recessive allele reside on the same chromosome; also calledTRANS Gen dominan terangkai dengan alel resesifnya pada satu kromosom, sedangkan alel-alel resesifnya terangkai pada kromosom homolognya Penulisannya : Ab/aB atau Ab aB
Coupling – the F1 configuration where both dominant alleles reside on the same chromosome; also called CIS The Development Of The Coupling Chromosome
Repulsion - the F1 configuration where one dominant and one recessive allele reside on the same chromosome; also calledTRANS The Development Of The Repulsion Chromosome
Recombination Occurs Less Frequently Between Closely Linked Genes • Physical crossing over is a normal meiosis event • Crossing-over pertukaran segmen dari kromatid-kromatid bukan non-sister kromatid dari sepasang kromosom homolog • The term used to describe crossing over is recombination • Recombination can occur between any two genes on a chromosome • The farther apart the two genes the more crossing over
A B A B meiosis I a b a b A B A B gamet parental A b gamet rekombinasi a B gamet rekombinasi a b a b gamet parental
Faktor-faktor yang mempengaruhi pindah silang • TEMPERATUR, temperatur kurang atau melebiji temperatur biasa dapat memperbesar kemungkinan pindah silang • UMUR, makin tua suatu individu makin kurang mengalami pindah silang • ZAT KIMIA tertentu dapat memperbesar kemungkinan terjadinya pindah silang • PENYINARAN SINAR X dapat memperbesar kemungkinan pindah silang • JARAK ANTAR GEN YANG TERANGKAI, makin jauh letak satu gen dengan gen lainnya, makin besar kemungkinan pindah silang • JENIS KELAMIN, umumnya jantan atau betina dapat mengalami pindah silang. Namun pada ulat sutera betina dan Drosophila jantan tidak pernah terjadi pindah silang
Determining Linkage Distances • By definition, one map unit is equal to one percent recombinant gametesor phenotypes • In honor of Morgan, one map unit is also called one centimorgan (cM) 1 mu = 1% = 1 cM
To determine the distance between two genes,divide the number of recombinant gametes by the total number of gametes Formula : Number of recombinants x 100% Total Number
Coupling Data prvg distance = ((151 +154)/2839)*100% = 10.7 m.u = 10.7 cM
Repulsion Data prvgdistance = ((157 + 146)/2335)*100% = 13.0 cM
Jarak Gen Coupling : pr vg 10,7 cM Repulsion : pr vg 13,0 cM
Remember these are estimates; the differences between the two estimates reflect random deviation • Neither estimate is incorrect; repeated experimentation would give a more accurate estimate
Deriving Linkage Distance And Gene Order From Three-Point Crosses • Analyzing three genes allows us to determine gene order as well as linkage distance • Need to create a F1 and follow deviation from a 1:1:1:1:1:1:1:1 ratio • What are the expected gametes when three linked genes are considered?
What are the parental genotypes? What is the gene order? What are the linkage distances?
What are the parental genotypes? • The genotypes most frequently found are the parental genotypes • ABC and abc are the parental genotypes
What is the gene order? * Menentukan susunan gen dengan memperhatikan Tipe Parental dan Tipe DCO • Pada Tipe Parental di-DCO-kan dan dibandingkan dengan hasil DCO pengamatan • The double crossover moves a non-parental allele of the central gene between two parental alleles • Gene Cis between genes Aand B(gene order = A C B)
What are the linkage distances? • Linkage distance equals the sum of the appropriate single cross plus all double crosses divided by total number of gametes Formula : • Jarak = SCO + DCO x 100% Jumlah Total
*JarakA - C = ((81+85+5+8)/1000)*100 = 17.9 cM *JarakC - B = ((27+30+5+8)/1000)*100 = 7.0 cM A C B 17,9 cM 7,0 cM