1 / 11

Warm Up 12/5

Warm Up 12/5. Is (-2, 3) a solution? 3x + y = -3 2x – 4y = 6 2) Find the solution by graphing y = -4 + x x + y = 6 Solve: y = x – 3 x + 2y = 3. No. (5, 1). (3, 0). Lesson 7.4A. Solving Linear Systems Using Elimination. Keys to Know. Solving with Elimination:

kellilouis
Download Presentation

Warm Up 12/5

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Warm Up 12/5 • Is (-2, 3) a solution? • 3x + y = -3 • 2x – 4y = 6 • 2) Find the solution by graphing • y = -4 + x • x + y = 6 • Solve: • y = x – 3 • x + 2y = 3 No (5, 1) (3, 0)

  2. Lesson 7.4A Solving Linear Systems Using Elimination

  3. Keys to Know Solving with Elimination: When you combine the equations to get rid of (eliminate) one of the variables. Possible solutions are: One Solution No Solutions Infinite Solutions

  4. Steps for Using Elimination • Write both equations in standard form (Ax + By = C) so that variables and = line up • Multiply one or both equations by a number to make opposite coefficients on one variable. • Add equations together (one variable should cancel out) • Solve for remaining variable. • Substitute the solution back in to find other variable. • Write the solution as an ordered pair • Check your answer

  5. Example 1: Step 1: Put both equations in standard form. Step 2: Check for opposite coefficients. Step 3: Add equations together Step 4: Solve for x Step 5: Substitute 2 in for x to solve for y (in either equation) Already Done 5x + y = 12 3x – y = 4 8x = 16 8 8 x = 2 5(2) + y = 12 10 + y = 12 y = 2 The solution is: (2, 2) y and –y are already opposites

  6. Your Turn Ex. 2 2x + y = 0 -2x + 3y = 8 Answer: (-1, 2)

  7. When we need to create opposite coefficients When you add these neither variable drops out SO…. We need to change 1 or both equations by multiplying the equation by a number that will create opposite coefficients. Example 3 3x + 5y = 10 3x + y = 2 3x + 5y = 10 -1(3x + y) = -1(2) 4y = 8 y = 2 Now plug (2) in for y. 3x + 2 = 2 X = 0 Solution is : (0,2) Multiply the bottom equation by negative one to eliminate the x 3x + 5y = 10 -3x – y = -2

  8. We will need to change both equations. We will have the y value drop out. 4) -2x + 3y = 6 x – 4y = -8 -2x + 3y= 6 -2x + 3y = 6 2( x – 4y) = -8(2) 2x - 8y = -16 -5 y = -10 y = 2 Now plug (2) in for y into any of the 4 equations. -2x + 3(2) = 6 -2x + 6 = 6 -2x = 0 x = 0 Solution is: (0, 2) Check your work!

  9. Your Turn Ex. 5 5x – 2y = 12 2x – 2y = -6 Ex. 6 -3x + 6y = 9 x - 2y = -3 Ex. 7 2x + 4y = 8 x + 2y = 3 (6, 9) 0=0 Infinite solutions 0=2 No Solutions

  10. What would happen when lines are coinciding? (The Same LINE or equation) Make up one for us to work out on the board. What happens when lines do not intersect? (parallel or same slope) Make up one for us to work out on the board. Conclusions: If the variables disappear and you have a true statement: Infinite solutions If the variables disappear and you have a false statement: No solutions

  11. Summary: • Of the three methods you have learned for solving systems of equations, which do you like the best and why, and which do you like the least and why? • HW: WS 7.4

More Related