1 / 14

Compound Angle Formulae

Compound Angle Formulae. 1. Addition Formulae. Example:. 2. Formulae Involving Double Angle (2A). Mixed Examples:. Substitute form the tan (sin/cos) equation. +ve because A is acute. Similarly:. 3-4-5 triangle !!!. A is greater than 45 degrees – hence 2A is greater than 90 degrees.

Download Presentation

Compound Angle Formulae

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Compound Angle Formulae 1. Addition Formulae Example:

  2. 2. Formulae Involving Double Angle (2A)

  3. Mixed Examples: Substitute form the tan (sin/cos) equation +ve because A is acute Similarly: 3-4-5 triangle !!! A is greater than 45 degrees – hence 2A is greater than 90 degrees.

  4. Q.E.D.

  5. (A Higher Question) The sine rule From the diagram: The sum of the angles of a triangle=180 As required

  6. TRIGONOMETRIC EQUATIONS Double angle formulae (like cos2A or sin2A) often occur in trig equations. We can solve these equations by substituting the expressions derived in the previous sections. Use sin2A = 2sinAcosA when replacing sin2A cos2A = 2cos2A – 1 if cosA is also in the equation cos2A = 1 – 2sin2A if sinA is also in the equation when replacing cos2A

  7. cos2x and sin x, so substitute 1-2sin2

  8. s a t c cos 2x and cos x, so substitute 2cos2-1 All S_ Talk C*&p ??

  9. 4 2 360o 0 -2 -4 Three problems concerning this graph follow.

  10. 4 2 360o 0 -2 -4 The max & min values of asinbx are 3 and -3 resp. The max & min values of sinbx are 1 and -1 resp. f(x) goes through 2 complete cycles from 0 – 360o The max & min values of csinx are 2 and -2 resp.

  11. From the previous problem we now have: Hence, the equation to solve is: Expand sin 2x Divide both sides by 2 Spot the common factor in the terms? Is satisfied by all values of x for which:

  12. From the previous problem we have: Hence:

More Related