1 / 22

2 Transmission Genetics Heritage from Mendel

2 Transmission Genetics Heritage from Mendel. Gregor Mendel. G. Mendel carried out his experiments from 1856 to 1863 in a small garden plot nestled in a corner of the St. Thomas monastery in the town of Brno He published the results and his interpretation in its scientific journal in 1866

kesler
Download Presentation

2 Transmission Genetics Heritage from Mendel

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 2 Transmission Genetics Heritage from Mendel

  2. Gregor Mendel • G. Mendel carried out his experiments from 1856 to 1863 in a small garden plot nestled in a corner of the St. Thomas monastery in the town of Brno • He published the results and his interpretation in its scientific journal in 1866 • Mendel’s paper contains the first clear exposition of the statistical rules governing the transmission of hereditary elements from generation to generation

  3. Each parent has two copies of the genetic information=homozygous Each gamete contains only one copy of the genetic information Random fertilization unites one copy from each parent So the F1 progeny contains two different variants (alleles) of the gene = heterozygous

  4. Dominance: All F1 offspring produce round seeds although their genotype is “Ww” because “W” is dominant and “w” is recessive • The genotypic ratio of the F2 is • 1/4 WW • 2/4Ww • 1/4ww • The phenotypic ratio of the F2 is • 3/4 Smooth • 1/4 Wrinkled

  5. Round vs. Wrinkled: Modern Context • The gene that determines the shape of a seed encodes an enzyme, starch-branching enzyme I (SBEI), required to synthesize a branched-chain form of starch known as amylopectin • Round (W) seeds contain amylopectin and shrink uniformly as they dry • Wrinkled (w) seeds have a mutation in the starch-branching enzyme I (SBEI) and cannot make amylopectin and shrink irregularly

  6. Monohybrid Genetic Cross Both F1 parents are heterozygous for the gene.

  7. unknown A method to figure out the genotype of the organism… Is this pea WW or Ww? Testcross Analysis ? We cross this organism with one we know is homozygous recessive. Then, the phenotypes of the can be attributed solely to the gene they inherited from the Unknown parent. • If the unknown is WW, all the progeny of the testcross will be Ww (dominant) progeny • If the unknown is Ww, 1/2 the progeny of the testcross will be Ww (dominant) and 1/2 the progeny will be ww (recessive)… As in the case shown on the right. ?

  8. Dihybrid Cross • two different traits, such as seed color (yellow vs. green) and seed shape (round vs. wrinkled) in the same cross = dihybrid cross • Breed F1 that you know are hybridforbothcharacteristics Phenotypic ratio of 9/16 : 3/16 : 3/16 : 1/16

  9. Independent Segregation • The Principle of Independent Assortment: Segregation of the members of any pair of alleles is independent of the segregation of other pairs in the formation of reproductive cells. Fig. 2.11

  10. Probabilities Multiplication Rule: The probability that two independent events, A and B, are realized simultaneously is given by the product of their separate probabilities What fraction would we expect to be Round AND Green 3/4 x 1/4 = 3/16 Addition Rule: The probability that one or the other of two mutually exclusive events, A or B, is the sum of their separate probabilities What fraction would we expect to be (Round and Green) OR (wrinkled and yellow) 3/16 + 3/16 = 6/16

  11. Pertubations on the theme • Incomplete dominance = the phenotype of the heterozygous genotype is intermediate between the phenotypes of the homozygous genotypes • Codominance means that the heterozygous genotype exhibits the traits associated with both homozygous genotypes • Penetrancerefers to the proportion of organisms whose phenotype matches their genotype for a given trait. A genotype that is always expressed has a penetrance of 100 percent • Epistasis refers to a gene interaction that results in a modified F2 dihybrid ratio other than 9 : 3 : 3 : 1. One gene essentially masks the expression of the other. (ABO blood groups are specified by three alleles IA, IB and IO) MutS and colon cancer

  12. Epistasis

  13. Complementation reveals whether two recessive mutations are alleles of different genes

  14. Pedigree Analysis • In humans, pedigree analysis is used to determine individual genotypes and to predict the mode of transmission of single gene traits

  15. Autosomal Dominant Traits • Huntington disease is a progressive nerve degeneration, usually beginning about middle age, that results in severe physical and mental disability and ultimately in death • Every affected person has an affected parent • ~1/2 the offspring of an affected individual are affected

  16. Autosomal Recessive Traits • Albinism = absence of pigment in the skin, hair, and iris of the eyes • Most affected persons have parents who are not themselves affected; the parents are heterozygous for the recessive allele and are called carriers • Approximately 1/4 of the children of carriers are affected

  17. How is this trait most likely inherited? If individual III5 and III6 have another child, what’s the probability that the child will be affected? Both individuals are carriers (heterozygous) for the recessive allele, so there is 1/4 chance the next child will be affected. If individual III1 and III7 were to have a child, what’s the probability that the child will be affected? IF both individuals are heterozygous for the recessive allele, there is 1/4 chance the next child will be affected. There is a 1/2 chance III1 is a carrier AND a 1/2 chance that III7 is a carrier AND a 1/4 chance that their child would be affected if they are carriers. 1/2 X 1/2 X 1/4 = 1/16

  18. How is this trait most likely inherited? If individual III4 and III6 have a child, what’s the probability that the child will be affected? Zero

  19. If the “nontaster”allele is relatively common in the population, how is this trait most likely inherited?

  20. How is this trait most likely inherited?

More Related