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ENTC 303: Announcements

ENTC 303: Announcements. Homework assignment No. 4 From Mott : Due Thursday, October 9 th before 3:35 pm For more information, go to: http://etidweb.tamu.edu/classes/entc303/ Exam I Tuesday, Oct 14 th Mott’s 1-7 Esposito’s 1-3 Homeworks 1-4. Closed book/closed notes

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ENTC 303: Announcements

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  1. ENTC 303: Announcements • Homework assignment No. 4 • FromMott: • Due Thursday, October 9th before 3:35 pm • For more information, go to: • http://etidweb.tamu.edu/classes/entc303/ • Exam I • Tuesday, Oct 14th • Mott’s 1-7 • Esposito’s 1-3 • Homeworks 1-4 • Closed book/closed notes • Yes, an equation sheet will be allowed • Double-sided is ok!

  2. ENTC 303: Announcements • Homework assignment No. 4 • FromMott: 6.36, 6.37, 6.61, 6.72, 6.78, 6.94, 7.3, 7.9, 7.17, 7.22, 7.23, 7.37. • FromEsposito: 3.59E and 3.62E. • Due Thursday, October 9th before 3:35 pm • For more information, go to: • http://etidweb.tamu.edu/classes/entc303/ • Exam I • Tuesday, Oct 14th • Mott’s 1-7 • Esposito’s 1-3 • Homeworks1-4 • Closed book/closed notes • Yes, an equation sheet will be allowed • Double-sided is ok!

  3. Total Energy and Conservation of Energy Principle • E = FE + PE + KE • Two points along the same pipe: E1 = E2 • Bernoulli’s Equation:

  4. For the venturi meter shown, determine the fluid velocity at A and the flowrate. The gage fluid’s SG is 1.25. Example 200 mm B 0.46 m A y 1.18 m 300 mm

  5. A h B Torricelli’s Theorem • For a liquid flowing from a tank or reservoir with constant fluid elevation, the velocity through the orifice is given by: where, h is the difference in elevation between the orifice and the top of the tank

  6. Flow Due to Falling Head A h(t) B Apply non-steady form of continuity equation

  7. Flow Due to Falling Head

  8. Torricelli’s Theorem • For a liquid flowing from a tank or reservoir with constant fluid elevation, the velocity through the orifice is given by: where, h is the difference in elevation between the orifice and the top of the tank Example: If h = 3.00 m, compute v2 h

  9. Real Systems • Friction losses: As fluids flow in pipes • Minor losses: due the presence of valves, elbows, pipe entrance, etc. • Motors: Turbines, actuators, etc. take energy from fluid • Pumps: Put energy into the fluid • The Bernoulli equation does not take these losses or gains into account

  10. http://commons.wikimedia.org/wiki/File:Piping_system_on_a_chemical_tanker.jpghttp://commons.wikimedia.org/wiki/File:Piping_system_on_a_chemical_tanker.jpg http://www.heatec.com/products_terminals/Piping/cwm.htm

  11. Energy Equation • Energyin = Energyout • Energyin + Gains - Losses = Energyout • hA = Energy added to the fluid by a pump • hR = Energy removed from the fluid by motors, etc. • hL = Energy losses due to friction and minor losses

  12. Conservation of Energy

  13. Example • Water flows from a reservoir at 1.2 ft3/sec. Calculate the energy lost from the system due to valves, elbows, pipe entrance and fluid friction. 12 ft Valve Elbow 13 ft 3 inches Elbow

  14. Example • Determine the energy loss due to a certain piece of apparatus. The inlet is a 2-in Schedule 40 pipe, the outlet is a 4-in Schedule 40 pipe. Calculate the energy loss between points A and B if water is flowing at 0.2 ft3/sec. The gage fluid is mercury (S.G. = 13.54) Not to scale! B 44 in 48 in 14 in A 10 in

  15. Pump Energy Energy PUMP = DPE + DKE + FE + LOSSES + REMOVED DPE = Potential Energy Differential DKE = Kinetic Energy Differential FE = Flow Energy

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