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CIRCLES AND SEGMENT MEASUREMENT

CIRCLES AND SEGMENT MEASUREMENT. Section 10-7. Jim Smith JCHS. COPY THESE NOTES AND DRAW THE DIAGRAMS. USE THESE AND THE PRACTICE PROBLEMS AT THE END AS EXAMPLES FOR THE CLASS ASSIGNMENT. a. d. c. b. THE PRODUCT OF THE PARTS OF ONE CHORD = THE PRODUCT OF THE PARTS OF

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CIRCLES AND SEGMENT MEASUREMENT

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  1. CIRCLES AND SEGMENT MEASUREMENT Section 10-7 Jim Smith JCHS

  2. COPY THESE NOTES AND DRAW THE DIAGRAMS. USE THESE AND THE PRACTICE PROBLEMS AT THE END AS EXAMPLES FOR THE CLASS ASSIGNMENT

  3. a d c b THE PRODUCT OF THE PARTS OF ONE CHORD = THE PRODUCT OF THE PARTS OF THE OTHER CHORD ab = cd

  4. 7 5 4 x 7x = 4(5) 7x = 20 7x= 20 7 7 X = 2.86

  5. Radius = 6, so one part= 6+x and the other part= 6-x The diameter is perpendicular to the chord, so it bisects the chord 6 . x FOIL 4 (6+x) (6-x) = 4∙4 36-x²=16 36-x²-36 = 16-36 -x²= -20 -x²/-1 = -20/-1 x² = 20 √x² = √20 X = 4.47

  6. Whole segment Outside part B A The outside part of segment AB x the whole segment AB = the outside part of segment CB x the whole segment CB C

  7. 5(x+5) = 7(15+7) little+little = big 5 x 7 Outside x Whole = Outside x Whole 15 5x+25 = 7(22) 5x+25 = 154 5x = 129 X = 25.8

  8. Tangent (the outside is also the whole) x 4 Outside x Whole = Outside x Whole x∙x = 4∙9 9 x² = 36 √x² = √36 X = 6 We know the whole so we don’t need to add the little parts

  9. TRY THESE 1 2 X 8 X 7 3 5 5 14

  10. Answers 1) 7X = 8(5) 7X = 40 X = 40/7 X = 5.71 2) 3(X+3) = 5(14) 3X+9 = 70 3X+9-9 = 70-9 3X = 61 X = 61/3 X = 20.33

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