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Lecture 10. Static Stability. General Concept. An equilibrium state can be stable or unstable Stable equilibrium: A displacement induces a restoring force i.e., system tends to move back to its original state
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Lecture 10 Static Stability
General Concept • An equilibrium state can be stable or unstable • Stable equilibrium: A displacement induces a restoring force • i.e., system tends to move back to its original state • Unstable equilibrium: A displacement induces a force that tends to drive the system even further away from its original state
A More Realistic Scenario Equilibrium
Small Displacement Stable.
Large Displacement Unstable.
Idea of Previous Slides • There may be a critical displacement magnitude • displacement < critical stable • displacement > critical unstable • (More about this shortly)
Atmospheric Stability Unsaturated Air
Consider a vertical parcel displacement, z • Assume displacement is (dry) adiabatic • Change in parcel temperature = -d z • Denote lapse rate of environment by
T=T0 - dz T = T0 - z Temp of displaced parcel temp of environment z T = T0 T = T0 Environment Parcel
Two Cases • Parcel temp. > environment temp. parcel less dense than environment parcel is buoyant • Parcel temp. < environment temp. parcel denser than environment parcel is negatively buoyant
Lapse Rates • Tparcel = T0 - dz • Tenv = T0 - z • Tparcel > Tenv if T0 - dz > T0 - z > d • Tparcel < Tenv if T0 - dz < T0 - z < d
Stability • > d resultant force is positive parcel acceleration is upward (away from original position) equilibrium is unstable • < d resultant force is negative parcel acceleration is downward (toward original position) equilibrium is stable
Graphical Depiction Temp of rising parcel z Stable lapse rate Unstable lapse rate Temperature
Saturated Air • Recall: Vertically displaced parcel cools/warms at smaller rate • Call this the moist-adiabatic rate, m • Previous analysis same with d replaced by m • Equilibrium stable if < m • Equilibrium unstable if > m
General Result • Suppose we don’t know whether a layer of the atmosphere is saturated or not • > d > m equilibrium is unstable, regardless • Equilibrium is absolutely unstable • < m < d equilibrium is stable, regardless • Equilibriumis absolutely stable
Continued • Suppose m < < d • Layer is stable if unsaturated, but unstable if saturated • Equilibrium is conditionallyunstable
Absolutely stable Conditionally unstable Absolutely unstable d m
Application • If a layer is unstable and clouds form, they will likely be cumuliform • If a layer is stable and clouds form, they will likely be stratiform
Example: Mid-Level Clouds • Suppose that clouds form in the middle troposphere • Unstable altocumulus • Stable altostratus
Deep Convection • Previous discussion not sufficient to explain thunderstorm development • Thunderstorms start in lower atmosphere, but extend high into the troposphere
Physics Review: Energy Object at height h h
Physics Review: Energy Remove support: Object falls h
Physics Review: Energy Let z(t) = height a time t z(t)
It Can Be Shown … potential energy kinetic energy (v = speed) As object falls, potential energy is converted to kinetic energy.
Available Potential Energy • Object may have potential energy, but it may not be dynamically possible to release it
Technically, PE = mgh, but lower energy state is inaccessible. The energy is unavailable. h
Energy Barriers To get from a to b, energy must be supplied to surmount the barrier. Energy needed: mghb hb a h b
Energy Barriers Now, ball can roll down hill. a h b
Energy Barriers Amount of PE converted to KE: mg(h + hb) Net release of energy: mg(h + hb) – mghb = mgh hb a h b
CAPE, CIN • CAPE: Convective Available Potential Energy • (Positive area) • CIN: Convective Inhibition • (Negative area at bottom of sounding)
Sounding Dry adiabat Saturated adiabat Positive area Negative area LCL
CAPE, CIN • CIN is the energy barrier • CAPE is the energy that is potentially available if the energy barrier can be surmounted