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Construction Geometry. Cones Surface Area Volume. Cones. A cone is a solid figure with a single circular base. Campbells. Geometric Solids. Geometric solids can be either “right” or “oblique”. Right solids have a vertical central axis while oblique solids (shown below) do not.
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Construction Geometry Cones Surface Area Volume
Cones • A cone is a solid figure with a single circular base. Campbells
Geometric Solids • Geometric solids can be either “right” or “oblique”. • Right solids have a vertical central axis while oblique solids (shown below) do not. • Our lessons will deal only with “right” solids.
Cones • Right cones have a vertical central axis while oblique cones do not. H r
Application • A cone has properties that are actually a combination of a circle and a right triangle.
A right triangle rotated on the center point of a circle forms a cone. Application
Application • The slant height (l) is used to find the surface area of a cone. l
Surface Area • The formula for the surface area of a cone is found on the Math Reference Sheet. • Surface Area = πrl + πr2
Surface Area l • Surface Area = πrl+ πr2 • πr2 = area of the circular base • πrl= area of cone portion r r l r
Practice #1 • Determine the surface area of the cone. • 1 = πr2 = π(3)2 = 9πm2 • 1 = πrl= π(3)(15) = 45 πm2 • Calculate the sum. • SA = 54 π m2 • ≈ 169.6 m2 3 m 15 m
Application • On construction jobs, most times concrete is delivered by a truck.
Application • Other times carpenters must mix concrete using a concrete mixer.
Application • Carpenters often calculate materials before starting a job to assure they have enough to finish without reordering. • Aggregate rock is delivered by the truckload. It is then dumped in a near-conical shape.
Application • When mixing concrete, carpenters often need to calculate materials that are on site.
Application • Aggregates like sand and gravel can be calculated by using the properties of a cone.
Practice #2 • Find the surface area of the pile of gravel. 10’ 16’
Practice #2 • For the surface area of the cone: • d = 16’ so r = 8’. • 1 = πr2 = π(8)2 = 64 πft2 • 1 = πrl= π(8)(10) = 80πft2 • Calculate the sum. • SA = 144π ft2 • ≈ 452.4 ft2 10’ 16’
Application • The vertical height is needed to find the volume. l h r
Volume • The formula for the volume of a cone is found on the Math Reference Sheet. • V = ⅓ πr2 h
Volume • Compare the formulas for the volume of a cylinder and cone. V = πr2 h V = ⅓ πr2 h
Volume • The volume of 1 cylinder = the volume of 3 cones of the same diameter and height. V = πr2 h V = ⅓ πr2 h
V = πr2 h V = ⅓ πr2 h Volume 1/3 1/3 1/3 1 cylinder 3 cones
9 ft 11 ft Practice #3 • Determine the volume of the cone shaped pile.
9 ft 11 ft Practice #3 • V = ⅓ πr2 h • V = ⅓ π(11 x 11)9 • V = 363 π ft3 • V ≈ 1140.4 ft3
10 ft 8 ft Practice #4 • The vertical height can be difficult to determine for a gravel pile; use the slant height to determine the volume.
10 ft 8 ft Practice #4 • V = ⅓ πr2 h - Use the Pythagorean Theorem to determine the vertical height. • 82 + h2 = 102 64+ h2 = 100 h2 = 36h= 6’ • V = ⅓ π(8x8)6 • V = 128 π ft3 • V ≈ 402.1 ft3 6 ft
Practice & Assessment Materials • You are now ready for the practice problems for this lesson. • After completion and review, take the assessment for this lesson.