1 / 12

LOGARITHM

LOGARITHM. GRADE X. LOGARITHMS. STANDARD OF COMPETENCY. Be able to solve problems related to exponents, roots, and logarithms. BASE COMPETENCY. To use the rules of exponents, roots, and logarithms . LOGARITHMS. INDICATORS. Changing exponents to be logarithms and vice versa .

koren
Download Presentation

LOGARITHM

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. LOGARITHM GRADE X

  2. LOGARITHMS STANDARD OF COMPETENCY Be able to solve problems related to exponents, roots, and logarithms BASE COMPETENCY • To use the rules of exponents, roots, and logarithms

  3. LOGARITHMS INDICATORS • Changing exponents to be logarithms and vice versa. • Using logarithm properties to solve a simple algebraic operation

  4. LOGARITHMS PROBLEM ? 32 = 9 2= ??? 3 Log 9 = 2

  5. LOGARITHMS Base, a>0, a≠1 Value a Log b = c Numerous, b>0

  6. LOGARITHMS Examples : 1. Express into logarithm form A. 23 = 8 C. 3x = 15 B. 25 = 32 D. 3(x+2) = 20 Answer : A. 23= 8  3 = 2Log 8 B. 25= 32  5 = 2Log 32 C. 3x= 15  x = 3Log 15 D. 3(x+2) = 20 x+2 = 3Log 20

  7. LOGARITHMS The LogarithmSFormulae m= aLog b am = b an = c bc = am. an = a m+n n = aLog c aLog(bc) = m + n = aLogb + aLog c aLog(bc) = aLog b + aLog c

  8. LOGARITHMS The Logarithm Formulae aLogbc = aLog b + aLog c aLog (b/c) = aLog b - aLog c aLogbn= n. aLog b a mLog b = (1/m) aLog b aLog a = 1, aLog 1 = 0 aLog b x bLog c = aLog c

  9. LOGARITHMS Examples : 2 Log 16 1. Find the values of the following A. B. C. Answer : A. B. 5 Log 125 Log 0,01 C. Log 0,01 = Log 10-2 = -2. Log 10 = -2.1 = -2 2 Log 16 = 2 Log 24 = 4. 2 Log 2 = 4 5 Log 125 = 5 Log 53 = 3 . 5 Log 5 = 3

  10. LOGARITHMS Examples : 2 Log 3 + 2 Log 8 – 2 Log 6 2. Simplify using logarithm properties ! A. B. Answer : A. B. 3Log 4 + 2.3 Log 2 – 2.3 Log 4 2 Log 3 + 2 Log 8 – 2 Log 6 = 2 Log (3x8) – 2 Log 6 = 2 Log (24/6) = 2 Log 4 = 2 3Log 4 + 2.3 Log 2 – 2.3 Log 4 = 3 Log 4 + 3 Log 22 – 3 Log 42 = 3 Log (4x4) – 3 Log 16 = 3 Log (16/16) = 3 Log 1 = 0

  11. LOGARITHMS EXERCISES • PAGE 55-56 • NO: 1 A, B, C, D, E • 2 A, B, D, E • 3 A, B, E • 4 A, B, C, D • 7 A, C • 8 • 9 A, B, C, D • 11 A, B

  12. LOGARITHMS THANK YOU

More Related