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REACTION STOICHIOMETRY(II) FACTOR LABEL LOGIC 2 H 2(g) + O 2 (g)  2 H 2 0 (g)

REACTION STOICHIOMETRY(II) FACTOR LABEL LOGIC 2 H 2(g) + O 2 (g)  2 H 2 0 (g). 1) CALCULATE THE YIELD OF OXYGEN IN GRAMS IF 4.0 GRAMS OF WATER IS CONSUMED IN THE ABOVE BALANCED REACTION. KNOWN 4.O g H 2 O. ( ). ( ). ( ). OBJECTIVE 16 g H 2 O. 2 mol H 2 O. =.

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REACTION STOICHIOMETRY(II) FACTOR LABEL LOGIC 2 H 2(g) + O 2 (g)  2 H 2 0 (g)

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  1. REACTION STOICHIOMETRY(II) FACTOR LABEL LOGIC 2 H2(g) + O2 (g) 2 H20(g) 1) CALCULATE THE YIELD OF OXYGEN IN GRAMS IF 4.0 GRAMS OF WATER IS CONSUMED IN THE ABOVE BALANCED REACTION. KNOWN 4.O g H2O ( ) ( ) ( ) OBJECTIVE 16 g H2O 2 mol H2O = 1 mol H2O 36 g O2 1mol H2O 18 gH2O 1 mol O2 CONVERT KNOWN TO MOLES FROM GRAMS, GRAMS CANCEL. MOLAR MASS OF O2 IS 18 G/MOL. GIVES MOLES OF KNOWN. MOLES = MASS MOLAR MASS MOLE RATIO: RATIO MOLES OF OBJECTIVE TO MOLES OF KNOWN., USE COEFFICIENTS OF BALANCED REACTION. THIS STEP GIVES MOLES OF OBJECTIVE. CONVERT MOLES OF OBJECTIVE TO GRAMS. THIS STEP GIVES GRAMS OF OBJECTIVE, WHICH THE QUESTION CALLED FOR

  2. REACTION STOICHIOMETRY FACTOR LABEL LOGIC 2KClO3 3 O2 (g) + 2 KCl 5) CALCULATE THE YIELD OF OXYGEN IN STP LITERS IF 254 GRAMS OF POTASSIUM CHLORATE IS DECOMPOSED IN THE ABOVE BALANCED REACTION. OBJECTIVE 67.2 L O2 KNOWN 245 g KClO3 ( ) ( ) ( ) = 1 mol KClO3 3 mol O2 22.4 L O2 2 mol KClO3 1mol O2 122.6 KClO3g MOLE RATIO: RATIO MOLES OF OBJECTIVE TO MOLES OF KNOWN., USE COEFFICIENTS OF BALANCED REACTION. THIS STEP GIVES MOLES OF OBJECTIVE. CONVERT MOLES OF OBJECTIVE TO LITERS OF GAS (I MOLE = 22.4 L) AT STP.

  3. REACTION STOICHIOMETRY FACTOR LABEL LOGIC 2CH3OH + 3 O2 (g) 2 CO2 (g)+4 H2O 2) CALCULATE THE TOTAL MASS OF PRODUCTS FORMED FROM 1 MOLE OF METHANOL. ( ) ( ) KNOWN 1 MOLE CH3OH OBJECTIVE 44 g L CO2 2mol CO2 44. g CO2 = 2 MOLE CH2OH 1mol CO2 KNOWN 1 MOLE CH3OH ( ) ( ) OBJECTIVE 36 g L H2O = 4mol H2O 18. g H2O 2 MOLE CH2OH 1mol H2O THE SUM OF BOTH PRODUCTS IS 80. g 1mol H2O

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