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Flux = = B • A = BA cos . Area vector = A is constructed normal to surface with a length = to its area π r 2. A. B. B. Flux = = B • A = BA cos . Area vector = A is constructed normal to surface with a length = to its area π r 2. A. B. B. Flux = = B • A = BA cos .
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Flux = = B•A = BA cos Area vector = A is constructed normal to surface with a length = to its area πr2. A B B
Flux = = B•A = BA cos Area vector = A is constructed normal to surface with a length = to its area πr2. A B B
Flux = = B•A = BA cos Area vector = A is constructed normal to surface with a length = to its area πr2. A B B
The AP B Ref Table writes A loop of wire having an area of 0.25 m2 contains a magnetic field intensity of 16 Teslas as shown. Find the magnetic flux through the loop. B
The AP B Ref Table writes A loop of wire having an area of 0.25 m2 has 8 Webers of magnetic flux passing through the loop. Find then strength of the magnetic field inside the loop. B
The E&M C Ref Tables write…….. A loop of wire having an area of 0.25 m2 has 8 Webers of magnetic flux passing through the loop. Find then strength of the magnetic field inside the loop. B
The AP B Ref Table writes And E&M C says…. A loop of wire having an area of 0.25 m2 has 8 Webers of magnetic flux passing through the loop. If the field collapsed in 4 seconds…….. a) find the EMF the loop would generate. b) tell which way current would flow to resist the change. c) What if there were 3 loops? B n
Two AP B formulas for induced E EMF induced by the rate of change in magnetic flux EMF induced by the speed you move a wire through a constant B field
Example problem: A 50 cm rod of resistance 2 ohms is moved across a 4 Tesla magnetic field at 2 m/s. Calculate….. a)…the EMF generated. b) …the current generated. The direction of I is defined by the cross product E = l v x B
The B Ref Table says • Force on a charge moving through a B field (q v x B) • Force on a wire carrying current through a B field (i l x B) The C Ref Table says
Find the direction and magnitude of the force on a 20 cm wire that carries 3 Amperes across a 4 Tesla field. • Force on a charge moving through a B field (q v x B) • Force on a wire carrying current through a B field (l ix B)
B Ref Table says • As you get farther away from the wire its field gets….. weaker Find the strength of a magnetic field 2 mm away from a wire carrying 10 amperes of current. C Ref Table says and call it Ampere’s Law