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Sin 20 = A x / 145 A x = 49.6 m Cos 35 = B x /105 B x = 86.0 m A x + B x = 135.6 m

A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.

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Sin 20 = A x / 145 A x = 49.6 m Cos 35 = B x /105 B x = 86.0 m A x + B x = 135.6 m

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  1. A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.

  2. A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.

  3. A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.

  4. Sin 20 = Ax / 145 Ax = 49.6 m Cos 35 = Bx/105 Bx = 86.0 m Ax + Bx= 135.6 m

  5. cos 20 = Ay / 145 Ay= 136.2 m sin 35 = Bx/105 By = 60.2 m Ay - By = 75.8 m

  6. 135.62 + 75.82 = C2 C = 155m tan angle = 75.8/135.6 angle = 29 degrees

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