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Heat of Combustion

Heat of Combustion. Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1. Energy (Q) = mc T C = 4.18 J g -1 K -1. Molar heat of combustion = ?. Heat of Combustion. Mass of water = 100g Temp rise of water = 15.0 C

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Heat of Combustion

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  1. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Molar heat of combustion = ?

  2. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270. Moles fuel = 1.34 / 56.4 = 0.023 Molar heat of combustion = 6270 / 0.023 = 272.6 ?

  3. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270. Moles fuel = 1.34 / 56.4 = 0.023 Molar heat of combustion = 6270 / 0.023 = 272.6 X

  4. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270. Moles fuel = 1.34 / 56.4 = 0.023 Molar heat of combustion = 6270 / 0.023 = 272.6 NO UNITS

  5. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270 J Moles fuel = 1.34 / 56.4 = 0.023 mol Molar heat of combustion = 6270 / 0.023 mol = 272.6 kJ mol-1 ?

  6. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270 J Moles fuel = 1.34 / 56.4 = 0.023 mol Molar heat of combustion = 6270 / 0.023 mol = 263.9 kJ mol-1 STILL NO UNITS X

  7. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg-1K-1 = 6270 J Moles fuel = 1.34g / 56.4 g mol-1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 272.6 kJ mol-1 ?

  8. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg-1K-1 = 6270 J Moles fuel = 1.34g / 56.4 g mol-1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 272.6 kJ mol-1 Wrong Significant Figures X

  9. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg-1K-1 = 6270 J Moles fuel = 1.34g / 56.4 g mol-1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 273 kJ mol-1 ?

  10. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg-1K-1 = 6270 J Moles fuel = 1.34g / 56.4 g mol-1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 264 kJ mol-1 Rounded before the end X

  11. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg-1K-1 = 6270 J Moles fuel = 1.34g / 56.4 g mol-1 Molar heat of combustion = 6270 J = 264 kJ mol-1 1.34g / 56.4 g mol-1 ?

  12. Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol-1 Energy (Q) = mc T C = 4.18 J g-1K-1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg-1K-1 = 6270 J Moles fuel = 1.34g / 56.4 g mol-1 Molar heat of combustion = 6270 J = 264 kJ mol-1 1.34g / 56.4 g mol-1 Much Better !

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