1 / 6

Working out Ks from solubility

Working out Ks from solubility. What is the Ks for CaCO 3 (s) when s (CaCO 3 (s))= 5.01 x 10 -6 mol L -1 ?. Write the equation for the solid at equilibrium with water. CaCO 3 (s)  Ca 2+ + CO 3 2-. Work out the concentrations of the aqueous ions.

lewis-olsen
Download Presentation

Working out Ks from solubility

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Working out Ks from solubility

  2. What is the Ks for CaCO3(s) when s(CaCO3(s))= 5.01 x 10-6 mol L-1 ? Write the equation for the solid at equilibrium with water CaCO3(s)  Ca2+ + CO32- Work out the concentrations of the aqueous ions. If the solubility of CaCO3(s)= 5.01 x 10-6 mol L-1 [Ca2+] = 5.01 x 10-6 mol L-1 [CO32-] =5.01 x 10-6 mol L-1

  3. Write the Ks expression. Remember do not include water or solids into the expression. Ks = [Ca2+][CO32-] Substitute the numerical values for [Ca2+] and [CO32-] into the expression. Ks = [5.01 x 10-6][5.01 x 10-6] Ks = [2.51 x 10-11]

  4. What is the Ks for Ag2S(s) 1.26 x 10-17 moles of Ag2S(s) dissolves in 1 litre of water? Write the equation for the solid at equilibrium with water Ag2S(s)  2Ag+ + S2- Work out the concentrations of the aqueous ions. If the solubility of Ag2S(s)= 1.26 x 10-17 mol L-1 [Ag+] = 2 x s(Ag2S) = 1.26 x 10-17 mol L-1 [S2-] =s(Ag2S)= 2.52 x 10-17 mol L-1

  5. Write the Ks expression. Remember do not include water or solids into the expression. Ks = [Ag+]2 [S2-] Substitute the numerical values for [Ag+] and [S2-] into the expression. Ks = [2.52 x 10-17]2 [1.26 x 10-17] Ks = [8.00 x 10-51]

More Related