1 / 10

If P is not the center point C , then the image point P  lies on .

Identifying Dilations. If P is not the center point C , then the image point P  lies on . The scale factor k is a positive number such that k = , and k  1. CP  CP. CP.

lillian-underwood
Download Presentation

If P is not the center point C , then the image point P  lies on .

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Identifying Dilations If P is not the center point C, then the image point P lies on . The scale factor k is a positive number such that k = , and k 1. CP CP CP Previously, you studied rigid transformations, in which the image and preimage of a figure are congruent. In this lesson, you will study a type of nonrigid transformation called a dilation, in which the image and preimage of a figure are similar. A dilation with center C and scale factor k is a transformation that maps every point P in the plane to a point P so that the following properties are true. If P is the center point C, then P=P.

  2. Identifying Dilations Reduction: k = = = Enlargement: k = = CP CP CP CP 5 2 1 2 3 6 Because PQR ~ P´Q´R´, is equal to the scale factor of the dilation. P´Q´ PQ The dilation is a reduction if 0 < k < 1 and it is an enlargement if k > 1. P P´ 6 5 P´ P 2 3 Q Q´ R • • C C R´ Q R´ Q´ R

  3. Identifying Dilations P 3 P´ 2 • C 2 3 2 3 Because = , the scale factor is k = . CP CP Identify the dilation and find its scale factor. SOLUTION This is a reduction.

  4. Identifying Dilations P´ 2 P P 3 P´ 1 2 • • C C 2 1 Because = , the scale factor is k = 2. CP CP Because = , the scale factor is k = . CP CP 2 3 2 3 Identify the dilation and find its scale factor. SOLUTION SOLUTION This is an enlargement. This is a reduction.

  5. Dilation in a Coordinate Plane Draw a dilation of rectangle ABCD with A(2, 2), B(6, 2), C(6, 4), and D(2, 4). Use the origin as the center and use a scale factor of . How does the perimeter of the preimage compare to the perimeter of the image? 1 2 C´ x 1 O 1 y A´ In a coordinate plane, dilations whose centers are the origin have the property that the image of P(x, y) is P´(kx, ky). SOLUTION Because the center of the dilation is the origin, you can find the image of each vertex by multiplying its coordinates by the scale factor. D C A B D´ A(2, 2)  A´(1, 1) B(6, 2)  B´(3, 1) B´ • C(6, 4)  C´(3, 2) D(2, 4)  D´(1, 2)

  6. Dilation in a Coordinate Plane Draw a dilation of rectangle ABCD with A(2, 2), B(6, 2), C(6, 4), and D(2, 4). Use the origin as the center and use a scale factor of . How does the perimeter of the preimage compare to the perimeter of the image? 1 2 C´ O y 1 1 x A´ In a coordinate plane, dilations whose centers are the origin have the property that the image of P(x, y) is P´(kx, ky). SOLUTION From the graph, you can see that the preimage has a perimeter of 12 and the image has a perimeter of 6. D C A B D´ A preimage and its image after a dilation are similar figures. B´ • Therefore, the ratio of the perimeters of a preimage and its image is equal to the scale factor of the dilation.

  7. Using Dilations in Real Life Shadow puppets have been used in many countries for hundreds of years. A flat figure is held between a light and a screen. The audience on the other side of the screen sees the puppet’s shadow. The shadow is a dilation, or enlargement, of the shadow puppet. When looking at a cross sectional view, LCP ~ LSH. = 59 74 12 SH LC LS CP SH = The shadow puppet shown is 12 inches tall (CP in the diagram). Find the height of the shadow, SH, for each distance from the screen. In each case, by what percent is the shadow larger than the puppet? LC = LP = 59 in.; LS = LH = 74 in. SOLUTION 59(SH) = 888 SH 15 inches

  8. Using Dilations in Real Life Shadow puppets have been used in many countries for hundreds of years. A flat figure is held between a light and a screen. The audience on the other side of the screen sees the puppet’s shadow. The shadow is a dilation, or enlargement, of the shadow puppet. When looking at a cross sectional view, LCP ~ LSH. SH CP 15 12 scale factor = = 1.25 So, the shadow is 25% larger than the puppet. LC = LP = 59 in.; LS = LH = 74 in.; SH15 inches SOLUTION To find the percent of size increase, use the scale factor of the dilation.

  9. Using Dilations in Real Life Shadow puppets have been used in many countries for hundreds of years. A flat figure is held between a light and a screen. The audience on the other side of the screen sees the puppet’s shadow. The shadow is a dilation, or enlargement, of the shadow puppet. When looking at a cross sectional view, LCP ~ LSH. = 66 74 12 SH LC LS CP SH = LC = LP = 66 in.; LS = LH = 74 in. SOLUTION 66 (SH) = 888 SH 13.45 inches

  10. Using Dilations in Real Life Shadow puppets have been used in many countries for hundreds of years. A flat figure is held between a light and a screen. The audience on the other side of the screen sees the puppet’s shadow. The shadow is a dilation, or enlargement, of the shadow puppet. When looking at a cross sectional view, LCP ~ LSH. SH CP 13.45 12 scale factor = = 1.12 So, the shadow is 12% larger than the puppet. LC = LP = 66 in.; LS = LH = 74 in.; SH13.45 inches SOLUTION To find the percent of size increase, use the scale factor of the dilation.

More Related