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Marvel ous Dimensional Analysis Activity

Marvel ous Dimensional Analysis Activity. These dominos are grouped. These dominos are grouped. Thor = 300 Hulk = 175 Superman = 500 The Thing = 225 Captain America = 410 Wolverine = 125 Spiderman = 275 . These dominos are grouped. Thor = 300 Hulk = 175 Superman = 500

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Marvel ous Dimensional Analysis Activity

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  1. Marvelous Dimensional Analysis Activity

  2. These dominos are grouped.

  3. These dominos are grouped. Thor = 300 Hulk = 175 Superman = 500 The Thing = 225 Captain America = 410 Wolverine = 125 Spiderman = 275

  4. These dominos are grouped. Thor = 300 Hulk = 175 Superman = 500 The Thing = 225 Captain America = 410 Wolverine = 125 Spiderman = 275

  5. ____ g Molar Mass (periodic table) ____ g Molar Mass (periodic table) ____ g Molar Mass (periodic table) 6.02 x 1023 particles 6.02 x 1023 particles 22.4 L gas @ STP 22.4 L gas @ STP 6.02 x 1023 particles 22.4 L gas @ STP 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole ____ g Molar Mass (periodic table) ____ g Molar Mass (periodic table) ____ g Molar Mass (periodic table) 6.02 x 1023 particles 6.02 x 1023 particles 22.4 L gas @ STP 22.4 L gas @ STP 6.02 x 1023 particles 22.4 L gas @ STP Substance A Substance B M M ___ mole ___ mole ___ mole mol mol V V ___ mole ___ mole ___ mole P P Mole Island

  6. ____ g Molar Mass Periodic table ____ g Molar Mass Periodic table ____ g Molar Mass Periodic table 22.4 L gas @ STP 22.4 L gas @ STP 22.4 L gas @ STP 6.02 x 1023 particles 6.02 x 1023 particles 6.02 x 1023 particles 6.02 x 1023 particles 6.02 x 1023 particles 6.02 x 1023 particles 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole 1 mole ____ g Molar Mass Periodic table ____ g Molar Mass Periodic table ____ g Molar Mass Periodic table 22.4 L gas @ STP 22.4 L gas @ STP 22.4 L gas @ STP Substance A Substance B M M ___ mole ___ mole ___ mole ___ mole ___ mole mol mol V V ___ mole ___ mole ___ mole P ___ mole ___ mole P Mole Island

  7. Balanced Chemical Equation: 5A2 + 3 G  2B + M 6.02 x 1023 particles How many molecules of substance B = 100 L substance A? 1 mole 2 x molecules “B” = 100 L “A” = ____ particles of “B” 5 1 mole 2 mol “B” 6.02 x1023 molecules “B” 1 mol “A” 22.4 L gas @ STP x molecules “B” = 100 L “A” = ___ molecules “B” 5 mol “A” 1 mol “B” 22.4 L “A” Substance A Substance B M M ___ mole mol mol V V “A” “B” P ___ mole P Mole Island

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