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CPS216: Data-Intensive Computing Systems Query Processing (Overview)

CPS216: Data-Intensive Computing Systems Query Processing (Overview). Shivnath Babu. Query Processing. Declarative SQL Query  Query Plan.

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CPS216: Data-Intensive Computing Systems Query Processing (Overview)

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  1. CPS216: Data-Intensive Computing SystemsQuery Processing (Overview) Shivnath Babu

  2. Query Processing Declarative SQL Query  Query Plan NOTE: You will not be tested on how well you know SQL. Understanding the SQL introduced in class will be sufficient (a primer follows). SQL is described in Chapter 6, GMUW. Focus: Relational System (i.e., data is organized as tables, or relations)

  3. SQL Primer We will focus on SPJ, or Select-Project-Join Queries Select <attribute list> From <relation list> Where <condition list> Example Filter Query over R(A,B,C): Select B From R Where R.A = “c”  R.C > 10

  4. SQL Primer (contd.) We will focus on SPJ, or Select-Project-Join-Queries Select <attribute list> From <relation list> Where <condition list> Example Join Query over R(A,B,C) and S(C,D,E): Select B, D From R, S Where R.A = “c”  S.E = 2  R.C = S.C

  5. Answer B D 2 x R A B C S C D E a 1 10 10 x 2 b 1 20 20 y 2 c 2 10 30 z 2 d 2 35 40 x 1 e 3 45 50 y 3 Select B,D From R,S Where R.A = “c”  S.E = 2  R.C=S.C

  6. How do we execute this query? Select B,D From R,S Where R.A = “c”  S.E = 2  R.C=S.C - Do Cartesian product - Select tuples - Do projection One idea

  7. Bingo! Got one... R X S R.A R.B R.C S.C S.D S.E a 1 10 10 x 2 a 1 10 20 y 2 . . c 2 10 10 x 2 . . Select B,D From R,S Where R.A = “c” S.E = 2  R.C=S.C

  8. Relational Algebra - can be used to describe plans Ex: Plan I B,D sR.A=“c” S.E=2  R.C=S.C X R S

  9. Relational Algebra Primer (Chapter 5, GMUW) Select:sR.A=“c” R.C=10 Project: B,D Cartesian Product: R XS Natural Join: R S

  10. Relational Algebra - can be used to describe plans Ex: Plan I B,D sR.A=“c” S.E=2  R.C=S.C X R S OR: B,D [sR.A=“c” S.E=2  R.C = S.C (RXS)]

  11. Another idea: B,D sR.A = “c”sS.E = 2 R(A,B,C) S(C,D,E) Plan II natural join Select B,D From R,S Where R.A = “c”  S.E = 2  R.C=S.C

  12. R S A B C s (R) s(S) C D E a 1 10 A B C C D E 10 x 2 b 1 20 c 2 10 10 x 2 20 y 2 c 2 10 20 y 2 30 z 2 d 2 35 30 z 2 40 x 1 e 3 45 50 y 3 Select B,D From R,S Where R.A = “c”  S.E = 2  R.C=S.C

  13. Plan III Use R.A and S.C Indexes (1) Use R.A index to select R tuples with R.A = “c” (2) For each R.C value found, use S.C index to find matching tuples (3) Eliminate S tuples S.E  2 (4) Join matching R,S tuples, project B,D attributes, and place in result

  14. =“c” <c,2,10> <10,x,2> check=2? output: <2,x> next tuple: <c,7,15> R S A B C C D E a 1 10 10 x 2 b 1 20 20 y 2 c 2 10 30 z 2 d 2 35 40 x 1 e 3 45 50 y 3 c 7 15 A C I1 I2

  15. Overview of Query Processing SQL query parse parse tree Query rewriting Query Optimization statistics logical query plan Physical plan generation physical query plan execute Query Execution result

  16. Example Query Select B,D From R,S Where R.A = “c”  R.C=S.C

  17. Example: Parse Tree <Query> <SFW> SELECT <SelList> FROM <FromList> WHERE <Cond> <Attribute> <SelList> <RelName> <FromList> <Cond> AND <Cond> B <Attribute> R <RelName> <Attr> <Op> <Const> D S R.A = “c” Select B,D From R,S Where R.A = “c”  R.C=S.C <Attr> <Op> <Attr> R.C = S.C

  18. Along with Parsing … • Semantic checks • Do the projected attributes exist in the relations in the From clause? • Ambiguous attributes? • Type checking, ex: R.A > 17.5 • Expand views

  19. SQL query Initial logical plan parse Rewrite rules parse tree Query rewriting Logical plan statistics logical query plan Physical plan generation “Best” logical plan physical query plan execute result

  20. Initial Logical Plan B,D Select B,D From R,S Where R.A = “c”  R.C=S.C R.A = “c” Λ R.C = S.C X R S Relational Algebra: B,D [sR.A=“c” R.C = S.C (RXS)]

  21. Apply Rewrite Rule (1) B,D B,D R.C = S.C R.A = “c” Λ R.C = S.C R.A = “c” X X R S R S B,D [sR.C=S.C [R.A=“c”(R X S)]]

  22. Apply Rewrite Rule (2) B,D B,D R.C = S.C R.C = S.C R.A = “c” X R.A = “c” S X R S R B,D [sR.C=S.C [R.A=“c”(R)] X S]

  23. Apply Rewrite Rule (3) B,D B,D R.C = S.C Natural join R.A = “c” X S R.A = “c” S R R B,D [[R.A=“c”(R)] S]

  24. SQL query Initial logical plan parse Rewrite rules parse tree Query rewriting Logical plan statistics logical query plan Physical plan generation “Best” logical plan physical query plan execute result

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