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Explore searching and sorting methods in Java, including sequential and binary search, sorting algorithms like selection sort and merge sort. Learn about algorithm efficiency and complexity. Implement custom ordering with Comparators.
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Building Java Programs Chapter 13: Searching and Sorting
Chapter outline • Searching and sorting in the Java class libraries • sequential and binary search • sorting • shuffling • custom ordering with Comparators • Program efficiency • algorithm analysis • complexity classes and Big-Oh notation • Implementing searching and sorting algorithms • binary search • selection sort • merge sort
Searching and sorting in the Java class libraries reading: 13.1
Sequential search • Imagine searching for a particular word in an ArrayList of words from a book: int index = words.indexOf(word); if (index >= 0) { System.out.println(word + " is word #" + index); } else { System.out.println(word + " is not found."); } • sequential search: One that examines each element of a list in sequence until it finds the target value or reaches the end of the list. • The indexOf method above uses a sequential search.
Binary search algorithm • binary search: An algorithm that searches for a value in a sorted list by repeatedly eliminating half the list from consideration. • Can be written iteratively or recursively • implemented in Java as method Arrays.binarySearch in java.util package • Algorithm pseudocode (searching for a value K): • Start out with the search area being from indexes 0 to length-1. • Examine the element in the middle of the search area. • If it is K, stop. • Otherwise, • If it is smaller than K, eliminate the upper half of the search area. • If it is larger than K, eliminate the lower half of the search area. • Repeat the above examination.
Using binarySearch • Java provides two binary search methods: • Arrays.binarySearch (for an array) // binary search on an array: int[] numbers = {-3, 2, 8, 12, 17, 29, 44, 58, 79}; int index = Arrays.binarySearch(numbers, 29); System.out.println("29 is found at index " + index); • Collections.binarySearch (for a List) // binary search on ArrayList with the same values: int index = Collections.binarySearch(list, 29); System.out.println("29 is found at index " + index); • Note that the values in the array / list are in sorted order. • If they are not, binarySearch is not guaranteed to work properly.
Sorting • sorting: Rearranging the values in a list into a given order (often into their natural ascending order). • One of the fundamental problems in computer science • Many sorts are comparison-based (must determine order through comparison operations on the input data) <, >, compareTo, …
Sorting in the class libraries • Java provides two sorting methods: • Arrays.sort (for an array) // demonstrate the Arrays.sort method String[] strings = {"c", "b", "g", "h", "d", "f", "e", "a"}; System.out.println(Arrays.toString(strings)); Arrays.sort(strings); System.out.println(Arrays.toString(strings)); • Output: [c, b, g, h, d, f, e, a] [a, b, c, d, e, f, g, h] • Collections.sort (for a List)
Shuffling • shuffling: Rearranging the elements of a list into a random order. • Java has a shuffle method for a List,Collections.shuffle: String[] ranks = {"2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King", "Ace"}; String[] suits = {"Clubs", "Diamonds", "Hearts", "Spades"}; ArrayList<String> deck = new ArrayList<String>(); for (String rank : ranks) { // build sorted deck for (String suit : suits) { deck.add(rank + " of " + suit); } } Collections.shuffle(deck); System.out.println("Top card = " + deck.get(0)); • Output (for one example run): Top card = 10 of Spades
Custom ordering with Comparators reading: 13.1
Custom ordering • Sometimes, the default ordering is not what you want. • Example: The following code sorts the strings in a case-sensitive order, so the uppercase letters come first.We may have wanted a case-insensitive ordering instead. String[] strings = {"Foxtrot", "alpha", "echo", "golf", "bravo", "hotel", "Charlie", "DELTA"}; Arrays.sort(strings); System.out.println(Arrays.toString(strings)); • Output: [Charlie, DELTA, Foxtrot, alpha, bravo, echo, golf, hotel] • You can describe a custom sort ordering by creating a class called a comparator.
Comparators • The Comparator interface in java.util describes a method for comparing two objects of a given type: public interface Comparator<T> { public int compare(T o1, T o2); } • Note that Comparator is a generic interface. • T will be replaced by the type of object you are actually comparing. • The compare method's job is to decide the relative ordering of the two given objects and return an appropriate integer: • < 0 if o1 comes before o2, • 0 if o1 and o2 are equivalent, • > 0 if o1 comes after o2.
Comparator example • The following Comparator compares Strings, ignoring case: public class CaseInsensitiveComparator implements Comparator<String> { public int compare(String s1, String s2) { return s1.toLowerCase().compareTo( s2.toLowerCase()); } }
Sorting with Comparators • The sorting methods shown previously can also be called with a Comparator as a second parameter. • The sorting algorithm will use that comparator to order the elements of the array or list. String[] strings = {"Foxtrot", "alpha", "echo", "golf", "bravo", "hotel", "Charlie", "DELTA"}; Arrays.sort(strings, new CaseInsensitiveComparator()); System.out.println(Arrays.toString(strings)); [Charlie, DELTA, Foxtrot, alpha, bravo, echo, golf, hotel] • Output: [alpha, bravo, Charlie, DELTA, echo, Foxtrot, golf, hotel]
Program efficiency reading: 13.2
Efficiency • efficiency: A measure of the computing resources used by a program, such as time, memory, or disk space. • time efficiency: How quickly a program runs • "Fast enough" is often relative to the task being performed. • 5 minutes to render a complex 3D scene for a movie is fast. • 5 minutes to search Google is slow. • Ways to measure the efficiency of a program: • empirical analysis: Program the algorithm, run it, and time it. • algorithm analysis: Applying techniques to mathematically estimate the algorithm's runtime without actually coding it.
Rules for algorithm analysis • Most individual statements take 1 unit of time to run. • When multiple statements are executed sequentially, their runtimes are added. • When statements are executed in a loop, the runtime is multiplied by the number of repetitions of the loop.
More examples • Larger statements can also occur sequentially, in which case their runtimes are added. • If larger statements are nested, their runtimes are multiplied.
Relative rates of growth • most algorithms' runtime can be expressed as a function of the input size N • rate of growth: measure of how quickly the graph of a function rises • goal: distinguish between fast- and slow-growing functions • we only care about very large input sizes(for small sizes, most any algorithm is fast enough) • this helps us discover which algorithms will run more quickly or slowly, for large input sizes
Growth rate example Consider these graphs of functions. Perhaps each one represents an algorithm: n3 + 2n2 100n2 + 1000 • Which growsfaster?
Growth rate example • How about now?
Range algorithm 1 • Let's examine the efficiency and growth rate of three algorithms for finding the range (difference between largest and smallest element) in an array. • First algorithm (looks at all pairs of values to find which pair is the largest and smallest): // returns the range of numbers in the given array public static int range(int[] numbers) { int maxDiff = 0; for (int i = 0; i < numbers.length; i++) { for (int j = 0; j < numbers.length; j++) { int diff = Math.abs(numbers[j] - numbers[i]); maxDiff = Math.max(maxDiff, diff); } } return maxDiff; }
Runtime of range 1 • Observation: runtime seems to roughly quadruple when input size is doubled
Range algorithm 2 • The first algorithm redundantly makes each comparison twice (when i <= j, when i > j). • Second, improved algorithm: public static int range2(int[] numbers) { int maxDiff = 0; for (int i = 0; i < numbers.length; i++) { for (int j = i + 1; j < numbers.length; j++) { int diff = Math.abs(numbers[j] - numbers[i]); maxDiff = Math.max(maxDiff, diff); } } return maxDiff; }
Runtime of range 2 • Observation: about twice as fast; same growth pattern • (runtime quadruples when input size is doubled)
Range algorithm 3 • We can discover the largest and smallest values in a single pass over the array, rather than using many nested passes over all values. • Third algorithm: public static int range3(int[] numbers) { int max = numbers[0]; int min = max; for (int i = 1; i < numbers.length; i++) { if (numbers[i] > max) { max = numbers[i]; } else if (numbers[i] < min) { min = numbers[i]; } } return max - min; }
Runtime of range 3 • Much faster than others • Runtime doubles when input size doubles
Complexity classes and Big-oh notation reading: 13.2
Big-Oh notation • complexity class: Category of algorithms' runtime based on relationship to input size. • Determined by the exponent of the most frequently executed line of code in the algorithm. • big-Oh notation: A shorthand for describing complexity classes. • Example: If the most frequently executed line of an algorithm runs approximately N3 times, we say the algorithm is "order N3" or O(N3) for short. • We are concerned with how the function grows when N is large. We are not picky about constant factors.
Hierarchy of Big-Oh • Complexity classes in increasing order of growth: • constant time O(1) • logarithmic O(log N) • linear O(N) • loglinear O(N log N) • quadratic O(N2) • cubic O(N3) ... • exponential O(2N) • ... • An algorithm from a lower complexity class will run much faster than one from a higher complexity class when the value of N becomes very large.
Program loop runtimes for (int i = 0; i < N; i += c) // O(N) <statements>; • Adding to the loop counter means that the loop runtime grows linearly when compared to its maximum value N. • Loop executes its body exactly N / c times. for (int i = 0; i < N; i *= c) // O(log N) <statements>; • Multiplying the loop counter means that the maximum value N must grow exponentially to linearly increase the loop runtime; therefore, it is logarithmic. • Loop executes its body exactly logcN times. for (int i = 0; i < N * N; i += c) // O(N2) <statements>; • The loop maximum is N2, so the runtime is quadratic. • Loop executes its body exactly (N2 / c) times.
More loop runtimes • Nesting loops multiplies their runtimes. for (int i = 0; i < N; i += c) { // O(N2) for (int j = 0; j < N; i += c) { <statements>; } } • Loops in sequence add together their runtimes, which means the loop set with the larger runtime dominates. for (int i = 0; i < N; i += c) { // O(N) <statements>; } for (int i = 0; i < N; i += c) { // O(N log N) for (int j = 0; j < N; i *= c) { <statements>; } }
Loop runtime problems • Approximate the value of the variable sum after the following code fragment, as an expression in terms of input size n. Use Big-Oh notation to describe the algorithm's overall runtime. int sum = 0; for (int i = 1; i <= N; i *= 2) { sum++; } for (int i = 1; i <= 1000; i++) { sum++; sum++; }
Loop runtime problems • Approximate the value of the variable sum after the following code fragment, as an expression in terms of input size n. Use Big-Oh notation to describe the algorithm's overall runtime. int sum = 0; for (int i = 1; i <= N; i++) { for (int j = 1; j <= i / 2; j += 2) { sum++; } }
Implementing binary search reading: 13.3
Recall: binary search • binary search: An algorithm that searches for a value in a sorted list by repeatedly eliminating half the list from consideration. • Can be written iteratively or recursively • Algorithm pseudocode (searching for a value K): • Start out with the search area being from indexes 0 to length-1. • Examine the element in the middle of the search area. • If it is K, stop. • Otherwise, • If it is smaller than K, eliminate the upper half of the search area. • If it is larger than K, eliminate the lower half of the search area. • Repeat the above examination.
Binary search example searching for value 16 min mid (too big!) max
Binary search example searching for value 16 min mid (too small!) max
Binary search example searching for value 16 min, mid, max (found it!)
Binary search pseudocode binary search array a for value i: if all elements have been searched, result is -1. examine middle element a[mid]. if a[mid] equals i, result is mid. if a[mid] is greater than i, binary search lower half of a for i. if a[mid] is less than i, binary search upper half of a for i.
Binary search code • The following code implements binary search: // Returns an index at which the target // appears in the given input array, or -1 if not found. // pre: array is sorted. public static int binarySearch(int[] numbers, int target) { int min = 0; int max = numbers.length - 1; while (min <= max) { int mid = (max + min) / 2; if (numbers[mid] == target) { return mid; // found it! } else if (numbers[mid] < target) { min = mid + 1; // too small } else { // numbers[mid] > target max = mid - 1; // too large } } return -1; // not found }
Runtime of binary search • How do we analyze the runtime of binary search? • The algorithm's runtime is dominated by a while loop. • Each pass of that loop cuts the search space in half. • How many times does this division in half take place? • 2repetitionsN • repetitions log2N
Implementing selection sort reading: 13.3
Selection sort • selection sort: orders a list of values by repetitively putting a particular value into its final position • more specifically: • find the smallest value in the list • switch it with the value in the first position • find the next smallest value in the list • switch it with the value in the second position • repeat until all values are in their proper places
Selection sort code • The following code implements selection sort: // places elements of the given array into sorted order public static void selectionSort(int[] a) { for (int i = 0; i < a.length - 1; i++) { // find index of smallest element int smallest = i; for (int j = i + 1; j < a.length; j++) { if (a[j] < a[smallest]) { smallest = j; } } swap(a, i, smallest); // swap smallest to front } } public static void swap(int[] list, int i, int j) { int temp = list[i]; list[i] = list[j]; list[j] = temp; }
Selection sort runtime • Observation: runtime roughly quadruples when input size is doubled • makes sense because the code performs two nested loops over the array of size N • its runtime should be O(N2)
Sorting practice problem • Consider the following array of int values: [22, 11, 34, -5, 3, 40, 9, 16, 6] • Perform the selection sort algorithm on this data.Write the contents of the array after each pass of the outermost loop of selection sort until the array is sorted.