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Example 3.2. Leg is horizontal, note moment arms are “a” and “b”. Leg is flexed at angle , moment arms are Now d1 = acos and d2 = bcos. Example 3.3. Example 3.4. A couple is formed by two parallel forces with equal magnitude and opposite directions.
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Example 3.2 Leg is horizontal, note moment arms are “a” and “b” Leg is flexed at angle , moment arms are Now d1 = acos and d2 = bcos
A couple is formed by two parallel forces with equal magnitude and opposite directions. On a rigid body a couple causes rotation and the rotational effect is called a couple-moment. M = F (d-b) + F b = F d is the moment about C which means that the couple has the same moment about any point in space lying between points A and B.
No effect of these forces and no moments as well since they cancel. These two now form a couple and a CCW moment equal to M=Fd All of these figures are mechanically equivalent. Overall effect of a pair of forces applied to a rigid body is zero if the forces have an equal magnitude and same line of action but act in opposite directions.
The moment of a force about a point is the vector product of the position and the force vectors. F = Fx i + Fy j r = rx i + ry j
So when we do the needed operations we get for The moment that: M = ( rx Fy – ry Fx ) k