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Average Atomic Mass Formula Mass

Average Atomic Mass Formula Mass. A quick review…. The Mole. The mole is the SI base unit for counting It is similar to a dozen (12 items) or a gross (144 items) or a ream (500 items) in that it always contains the same NUMBER of items 6.022 10 23 items. The Mole and Average Atomic Mass.

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Average Atomic Mass Formula Mass

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  1. Average Atomic MassFormula Mass A quick review…

  2. The Mole • The mole is the SI base unit for counting • It is similar to a dozen (12 items) or a gross (144 items) or a ream (500 items) in that it always contains the same NUMBER of items • 6.0221023 items

  3. The Mole and Average Atomic Mass • The number of atoms contained in exactly 12.000 grams of Carbon-12 is used as the standard counting unit • The number of atoms contained in 12.000 g of the Carbon-12 isotope is 6.0221023 • Avogadro’s Number • The same number of atoms is contained in a mass equal to the Average Atomic Mass (in grams) for each element

  4. Formula Mass (or Weight)aka, Molecular Mass (or Weight) • The formula mass is the sum of the atomic masses of all of the atoms in a compound • The same number of atoms (or molecules, or formula units) is contained in a mass equal to the Average Atomic Mass/Formula Mass (in grams) for each element (or compound)

  5. Using the Mole • The mole can be used in conversion factors because: • 1 mol = 6.0221023 things • 1 mol = (Average Atomic Mass/Formula Mass) grams of any substance • 6.0221023 formula units = (Average Atomic Mass/Formula Mass) grams of any substance

  6. Perform the following calculations… • Number of moles in: • 0.039 g palladium (Pd) • 8200 g iron • 5.64 kg barium (Ba) • 45.0 g acetic acid (CH3COOH) • 7.04 g of lead (II) nitrate • 50.0 kg of ammonium sulfate • Remember those sig digs and unit conversions!

  7. Perform the following calculations… • Number of atoms/formula units in: • 17.0 mol germanium (Ge) • 2.0×106 mol carbon • 0.00300 mol strontium nitrate • Strontium = Sr • 4.27 mol tungsten (VI) oxide • Tungsten = W

  8. Perform the following calculations… • Number of grams in: • 8.22×1023 atoms rubidium (Rb) • 9.96×1026 atoms tellurium (Te) • 8.39×1023 molecules of fluorine • 7.004×1026 molecules of CH3Cl • 5.00×1021 formula units aluminum hydroxide

  9. Perform the following calculations… • Number of: • Hydrogen atoms in 1.366 mol of NH3 • Chloride ions in 6.94 mol barium chloride • Boron atoms in 3.00 g of boron tribromide • Chlorine atoms in 50.0 g of calcium chlorate

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