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物理化學 (2)- 作業解答 -02

物理化學 (2)- 作業解答 -02.

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物理化學 (2)- 作業解答 -02

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  1. 物理化學(2)-作業解答-02 下列敘述何者正確？ (A)同一種反應物，會因為catalyst的不同而使反應速率加快情形不同，但產物一定會相同 (B)一般認定加入catalyst使activation energy降低而加快反應 (C)當catalyst因產物或其他雜物使其失去功能且無法再生時，稱其poisoned (D)溫度升高，exothermic reaction的反應速率會變慢 (E)化學反應若要把化學鍵打開再形成生成物者，則反應速率較快 (F)根據Collision theory，反應物若沒有產生碰撞，是不會反應的 (G) activation energy可以是正值或負值 (H)所謂activation energy是指把反應物變成”activated complex”所需加入的能量 Ans: BFH A 的答案：產物可能不相同 C 的答案：poisoned 的觸媒可 能可以再生 D 的答案：不管是吸熱或放熱反應 ，會變快 E 的答案：反應速率較慢 G 的答案： activation energy 是正值

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