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Sin A =

A. 5. 4. Sin A =. C. B. 3. A. 5. 4. Tan B =. C. B. 3. A. 5. 4. Cos B =. C. B. 3. A. 5. 4. Cos A =. C. B. 3. A. 50. 14. Cos A =. 48. C. B. A. 50. 14. Tan A =. 48. C. B. A. 50. 14. Sin B =. 48. C. B. Toa. Cah. Sin (25) = 10 sin(25) = x

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Sin A =

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  1. A 5 4 Sin A = C B 3

  2. A 5 4 Tan B = C B 3

  3. A 5 4 Cos B = C B 3

  4. A 5 4 Cos A = C B 3

  5. A 50 14 Cos A = 48 C B

  6. A 50 14 Tan A = 48 C B

  7. A 50 14 Sin B = 48 C B

  8. Toa Cah Sin (25) = 10 sin(25) = x x = 4.23m Soh 10m x 25

  9. Toa Cah x Soh 12cm Tan (70) = 12 tan(70) = x x = 32.97cm 70

  10. Toa Cah 8” Tan (41) = x tan(41) = 8 x = x = 9.20” Tan (49) = 8 tan(49) = x x = 9.20” Soh x 41 OR . . .

  11. Toa Cah cos (51) = x cos(51) = 5.75 x = x = 9.14 km Soh x 51 5 km

  12. Soh Toa Cah 36.9 = 5 3 

  13. Soh Toa Cah 48.6 = 8  2

  14. Find the measures of the acute angles in an 8-15-17 triangle Since you have all 3 sides, you can use whichever ratio you want. I’m going to use sin to find , then subtract to find . = 90 -  = 90 – 32.2 = 61.9 28.1 = 17  8  15

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