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Discrete Mathematics by Meri Dedania Assistant Professor MCA department Atmiya Institute of Technology & Science Yogidham Gurukul Rajkot. Group Theory. Definition of Group A Group < G , > is an algebraic system in which on G satisfies four condition Closure Property
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Discrete Mathematics by MeriDedania Assistant Professor MCA department Atmiya Institute of Technology & Science YogidhamGurukul Rajkot
Definition of Group A Group < G , > is an algebraic system in which on G satisfies four condition • Closure Property For all x , y G x y G • Associative Property For all x , y , z G x (y z) = (x y) z • Existence of Identity element There exists an element e G such that for any a G x e = x = e x • Existence of Inverse Element For every x G ,there exists an element denoted by a-1 G such that x-1 x = x x-1 = e
Definition of abelian Group A Group < G , >in which the operation is commutative is called abelian Group i.e. a,b G , a b = b a Example < Z , + > is Abelian Group < Q , + > is abelian Group
Properties of Group Theorem 1 : Let e be an identity element in group < G , > , Then e is unique Proof : • Let e and e` are two identity in G • e e` = e if e` is identity • e e` = e` if e is identity • since ee` is unique element in G • e = e`
Theorem 2 : Inverse of each element of a group < G , > is unique Proof : • Let a be any element of G and e the identity of G • Suppose b and c are two different inverse of a in G. • a b = e = b a (if b is an inverse of a) • a c = e = c a (if c is an inverse of a) • Now , b = b e = b ( a c) = (b a) c = e c = c Thus a has unique inverse
Theorem 3 : if a-1 is the inverse of an element a of group < G , > then (a-1)-1=a Proof : • Let e be the identity of Group < G , > • a-1 a = e • (a-1)-1 (a-1 a) = (a-1)-1 e • ((a-1)-1 a-1) a = (a-1)-1 • e a = (a-1)-1 • (a-1)-1 = a
Theorem 4 : If < G , > be a group then for any two elements a and b of < G , > prove that ( a b )-1 = b-1 a-1 rule of reversal Proof : • Let a-1 and b-1 are inverse of a and b respectively and e be the identity • a a-1 = e = a-1 a • b b-1 = e = b-1 b • (a b) (b-1 a-1) = [(a b) b-1] a-1 • = [a (b b-1)] a-1 • = [a e] a-1 • = a a-1 • = e • Similarly , (b-1 a-1) (a b) = e • This show that b-1 and a-1 is inverse of b and a • Hence , ( a b )-1 = b-1 a-1
Cancellation Property : if a , b and cbe any three elements of a group < G , > then ab = ac b = c left cancellation ba = ca b = c right cancellation Proof : • Let a G and also a-1 G • aa-1 = e = a-1a • where e is identity of G • Now , ab = ac • a-1(ab) = a-1 (ac) • (a-1 a) b = (a-1 a)c • e . b = e . c • b =c • similarly , ba = ca • b = c
Permutation Group Definition of Permutation A permutation is one to one mapping of non empty set P , say onto itself Example : Let S = {1,2,3} Then function f : S S f(1) = 2 f(2) = 3 f(3) = 1 Then permutation P1 = P2 =
P3 = P4 = P5 = P6 = There are n! of pattern of expressing Permutation . So if Set has 3 elements then pattern of expressing permutation is 3! = 6
Equality of Permutations : • Let f and g be two permutations defined on a non empty set P. Then f = g if and only if f(x) = g(x) x P • Example • Let S = {1,2,3,4} and let permutation f and g are equal or not.. f = g = • Let S = {1,2,3,4} and let permutation f and g are equal or not.. f = g =
Permutation Identity • An Identity permutation on S , denoted by I , is defined as I(a) = a a S • For example : f = Note : In identity permutation the image of element is element itself
Composition of Permutation ( Product of Permutation) • Let f and g be two arbitrary permutations of like degree , given by, f = g = on non empty set A. Then the composition (or Product) of f and g is defined as Continue…
f g = = • Example Let P1 = P2= P3 = Check P1 (P2 P3) = (P1 P2) P3
Inverse Permutation • Every permutation f on set P = {a1,a2,a3,…,an} Possesses a unique inverse permutation , denoted by f-1 thus if f = Then f-1 =
Cyclic Permutation • Let t1,t2,…..,tr be r distinct elements of the set P = {t1,t2,…., tn}.Then the permutation p : P P is defined by p(t1) = t2 , p(t2) = t3,….,p(tr-1)= tr, p(tr)=t1 is called a cyclic permutation of length r. • Example : The permutation P = is written as (1,2) , (3,4,6) , (5).. The cycle (1,2) has length 2 , The cycle length 3,The cycle 1.
Definition of Cyclic Group • If there exists an element a G for some group < G , > such that every element of G can be written as some power of a , that is an for some integer n. then a Group < G , > is said to be cyclic Group • Every Cyclic Group is abelian • Example for set A = { , , ,} and binary operation
If < G , > is an abelian group , then for all a , b G show that ( a b )n = an bn Solution ( a b )n = an bn ( a b )n+1=an+1 bn+1 ( a b )n+2=an+2 bn+2 Now , ( an bn ) ( a b ) = ( a b )n+1 = ( an+1 bn+1 ) (bn a )=(a bn) By cancellation , similarly bn+1 a = a bn+1 Again bn+1 a = b(bn a) = b(abn) i.e., abn+1 = b(abn)
Show that in a Group < G , > , if for any a, b G , ( a b )2 = a2 b2, then <G , > must be abelian Solution : Let < G , > be a Group and let a , b G ( a b )2 = a2 b2 ( a b ) ( a b ) = ( a a) ( b b ) • a ( b a) b = a ( a b) b • By left and right cancellation property • b a = a b • Thus we have a b = b a . a,b G • Hence < G , >is an abelian Group
Show that if every element in a group is its own inverse , then the group must be abelian Solution : Let a , b G • a b G (by closure property) Now, a-1 = a and b-1 = b • ( a b)-1 = a b Now, ( a b)-1 = a b • b-1 a-1 = a b • b a = a b • Thus we have a b = b a , a,b G • Hence < G , >is an abelian Group
Write down Composition table for <Z7, +5> and <Z7*, 7> where Z7* = Z7 - {0}
Show that < {1} , > and < {1 , -1} , > are the only finite groups of nonzero real numbers under the operation of multiplication Solution:
Sub Group and Homomorphism • Definition of Sub Group : • Let < G , > be a Group and S G, such that it satisfies the following condition: • e G , Where e is the identity of < G , > • For any a S , a-1 S • For a , b S , a b S Then < S , > is called Sub Group of <G , > • For any group <G , > , <{e} , > and <G , > are Trivial Sub Groups of <G , >. • Let <Z-{0}, X> is a Group then <{1}, X> & <Z,X> are Trivial Sub group of <Z, X> • All other subgroups of <G , > are called Proper Subgroup • Let < {,-1,0,1} , X > is Proper subgroup of <Z , X >
Theorem : A subset S of G is a subgroup of < G , > iff for any pair of elements a , b S , a b-1 S Proof : • Assume that S is a subgroup • if a , b S then b-1 S and a b-1 S • To prove the converse , let us assume that a , b S and a b-1 S for any pair a , b. • taking b = a , a a-1 = e S • From e , a, b S e a-1 = a-1 S • Similarly , b-1 S. • Finally , because a and b-1 are in S , we have a b S. • Hence , < S , > is a sub group of < G , >
Definition of Group Homomorphism • Let < G , > and < H , > be two Group. A mapping g : G H is called a group homomorphism from < G , > to < H , > if for any a , b G • g (a b) = g(a) g(b) • g(eG) = eH • g(a-1) = [g(a)]-1
Definition of Group Isomorphism • Let f : < G , > < H , >.if f is one to one and onto. Then Group is called isomorphism • A homomorphism f : < G , > < H , > is called an endomorphism • A Isomorphism f : < G , > < H , > is called an automorphism
Definition Kernal of Homomorphism • Let < G , > and < H , > be two Groups and let f is homomorphism of G into H. The set of elements of G which are mapped into eH , the identity of H is called the kernal of the homomorphism and is denoted by Kf or Ker(f)
Theorem : The Kernal of homomorphism f : <G , > < H , > is sub group of < G , > Proof : • Here f : < G , > < H , > is homomorphism • Ker (f) = {x G | f(x) = eH identity element of H} • k (f) because eG K(f) (f(eG)=eH) • let a , b Kf • f (a) = eH & f(b) = eG • Now, f(ab-1) = f(a) . f(b-1) • = f(a) . [f(b)]-1 • = eH . eH-1 • = eH . eH • = eH • ab-1 Kf • Kf is a sub group of < G , >
Show that every interval of lattice is a sub lattice of a lattice Proof: • Let < L , > be a lattice and a , b L • a , b • a a b • a [ a , b ] • also [a , b] = {x L | a x b} L • Let x , y [ a , b ] • a x b , a y b • a a x y b b • a a x y b b • a x y b • a x y b • x y [ a , b ] and x y [ a , b ] • [ a , b ] is sub lattice of the lattice < L , >
Draw Hasse Diagram of the poset {2,3,5,6,9,15,24,45},D . Find (i) Maximal and Minimal elements (ii) Greatest and Least members, if exist. (iii) Upper bound of {9,15} and l.u.b. of{9,15} , if exist. (iv) Lower bound of {15,24} and g.l.b. of{15,24} , if exist.
Definition Of Right Cosets • Let G be a Group and H is any sub Group of G. Let a be any element of G . Then set Ha = {ha : hH} is called a right coset of H in G generated by a. • Definition of Left Cosets • Let G be a Group and H is any sub Group of G. Let a be any element of G . Then set aH = {aH : hH} is called a right coset of H in G generated by a.
Lagrange’s Theorem : • The order of each sub group of a finite group G is a divisor of the order of G • Index in G : • The number of left cosets of H in G is called index of H in G. • Definition of Normal subgroup: • A sub group < H , > is sub group of < G , > is called a normal sub group if for any a G , aH = Ha
Fins the Sub group of < Z12 , +12 > • show that <{1,4,13,16} , 17> is subgroup of < Z17* , 17 > • Show that every sub group of abelian group is normal • Let x G and h H • Xhx-1 = xx-1h = eh = h • x G and h H • xhx-1 H • i.e. xH = Hx • H is normal subgroup of G
Definition of Irreflexive • A relation R on a set A is irreflexive if aRa for a A, if (a,a) R • For example • A = {1,2,3,4} • R = {<1,1>,<1,2>,<2,3>,<1,3>,<4,4>} • R = {<1,3>,<2,1>}