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11/7/16 Entry 173 – Objective

11/7/16 Entry 173 – Objective. I will review and continue developing my understanding of uniform probability models, including the complement of an event. Entry 174 – Probability Games.

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11/7/16 Entry 173 – Objective

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  1. 11/7/16 Entry 173 – Objective I will review and continue developing my understanding of uniform probability models, including the complement of an event.

  2. Entry 174 – Probability Games • Have you ever played a game where everyone should have an equal chance of winning, but one person seems to have all luck? If there is an equal chance for each player to win a game, it is considered to be a fair game. If is not equally likely for each player to win, a game is considered to be unfair.

  3. Entry 175– Pick a Card • 5-23 What is the probability of picking the following card from the deck? • a. P(black)? • b. P(club)? • c. If you drew a card from the deck and replaced it, and if you repeated this 100 times, about how many times would you expect to draw a face card ( king, queen, or jack)? • * There are 52 cards in a standard deck • There are four different suits: Diamonds, Clubs, Hearts, and Spades. There are thirteen cards, Ace - Two - Three… Ten - Jack - Queen - King in each suit

  4. #175 Answer • a. 26/52 = ½. 50% or 0.5 • b. 13/52 = ¼. 25% or 0.25 • c. There are 12/52 face cards, and 100 is just less than twice 52, so since 2x12=24, about 22 or 23 times.

  5. Entry 176 - Complement • 5-24 When finding the probability that something will not happen, you are finding the probability of the complement • What is the probability you do not get a club, written P (not club)? • What is P(not face card)?

  6. #176 Answer • 39/52 = ¾, 75% or 0.75 • 40/52 = 10/13, about 77%, or 0.769

  7. Entry 177 – Do it myself • Rob decided to play a card game with his friend, Travis. He told Travis that if he picked a black card with a value of nine or greater, Travis will win. ( Jack, queens, and kings are considered to be greater than nine) If Rob picked a red card with a value of less than nine, Rob would win.( Aces are considered to have the value of one in this case.) • What is the probability that Travis will win? • What is the probability that Rob will win? • According to the definition in the introduction to this lesson, is this a fair game? Why or why not?

  8. #177 Answer • a. 10/52 =5/26 =0.19 = 19% • b. 16/52 = 8/26 = 4/13 = 0.31 = 31% • c. NO. Rob has a better chance of winning.

  9. Entry 178 - Homework • 5-29 • 5-30 • 5-31

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