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1) How many moles of water are in an 82.3g sample?

1) How many moles of water are in an 82.3g sample?. 82.3g water. 1mole water. =. x. 1. 18.02g water. 4.57 mole water. 2) How many grams of oxygen are in a sample of gas that has a volume of 8.61L at STP?. 32g O 2. 8.61L O 2. 1 mole O 2. x. x. =. 1. 22.4L O 2. 1 mole O 2.

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1) How many moles of water are in an 82.3g sample?

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  1. 1) How many moles of water are in an 82.3g sample?

  2. 82.3g water 1mole water = x 1 18.02g water 4.57 mole water

  3. 2) How many grams of oxygen are in a sample of gas that has a volume of 8.61L at STP?

  4. 32g O2 8.61L O2 1 mole O2 x x = 1 22.4L O2 1 mole O2 12.3g O2

  5. 3) How many liters of gas are contained in a sample that is made up of 42.48g of sulfur trioxide at STP?

  6. 22.4L SO3 42.48g SO3 1 mole SO3 x x = 1 80.06g SO3 1 mole SO3 11.89L SO3

  7. 4) How many formula units are present in a Iron (III) oxide sample that contains 1.68x1025 atoms

  8. 1.68x1025 atoms 1 F.U. Fe2O3 = x 1 5 atoms 3.36x1024 F.U. Fe2O3

  9. 5) How many atoms are present in a sample containing 1.96g of ammonium phosphate?

  10. 1.96g (NH4)3PO4 1 mole (NH4)3PO4 6.02x1023F.U. (NH4)3PO4 x x 1 mole (NH4)3PO4 1 149.12g (NH4)3PO4 20 atoms x = 1.58x1023 atoms 1 F.U. (NH4)3PO4

  11. 6) How many liters of gas are contained in a sample of chlorine that contains 3.2x1011atoms?

  12. 3.2x1011 atoms Cl 1 mole Cl2 1 molecule of Cl2 x x 1 2 atoms Cl 6.02x1023 molecules Cl2 22.4L Cl2 x = 6.0x10-12L Cl2 1 mole Cl2

  13. 7) How many atoms of oxygen are contained in a 53.82g sample of aluminum sulfate?

  14. 53.82g Al2(SO4)3 1 mole Al2(SO4)3 6.02x1023F.U. Al2(SO4)3 x x 1 mole Al2(SO4)3 1 342.14g Al2(SO4)3 12 atoms O x = 1.136x1024 atoms O 1 F.U. Al2(SO4)3

  15. 8) How many formula units of hydrochloric acid are present in a 75.0mL solution if it has a concentration of 0.258M?

  16. 0.258moles HCl 75.0mL HCl Soln. 1L HCl Soln. x x 1000mL HCl Soln. 1L HCl Soln. 1 • 6.02x1023F.U. HCl x = 1.16x1022 F.U. HCl 1 mole HCl

  17. 9) What is the length of a copper wire (cylinder) that has a diameter of 0.0200cm and contains 4.91x1022 copper atoms? Vcyl=πr2h, Dcu = 8.96g/mL

  18. 63.55g Cu 4.91x1022atoms Cu 1 mole Cu x x 1 1 mole Cu • 6.02x1023atoms Cu 1 cm3Cu = x 0.5785 cm3 8.96g Cu 0.5785cm3 = 3.14(0.0100cm)2h Vcyl=πr2h h = 1840cm

  19. Answers • 1) 4.57 mole water • 2) 12.3g O2 • 3) 11.89L SO3 • 4) 3.36x1024 F.U. Fe2O3 • 5) 1.58x1023atoms • 6) 6.0x10-12L Cl2 • 7) 1.136x1024 atoms O • 8) 1.16x1022 F.U. HCl • 9) 1840cm

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