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Q 3 Revisited

Q 3 Revisited. Why did the two different methods produce different results?. The question was inconsistent!. Initial momentum was 0.117 kgms -1. One of the momentum vectors was at an angle of 50 degrees. The other vector was at 90 degrees to that one.

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Q 3 Revisited

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  1. Q 3 Revisited Why did the two different methods produce different results?

  2. The question was inconsistent! Initial momentum was 0.117 kgms-1 One of the momentum vectors was at an angle of 50 degrees. The other vector was at 90 degrees to that one. Now the triangle is fixed! All quantities can be calculated. There is no freedom to make up results.

  3. Calculate what the velocities should have been. Initial momentum was 0.117 kgms-1 40 degrees 50 degrees. 90 degrees The masses have a mass of 0.065 kg.

  4. Trigonometry. Initial momentum was 0.117 kgms-1 50 degrees. 40 degrees p2 p1 90 degrees Cos 40 = p1 / 0.117 p1 = 0.117 x cos 40 = 0.0896 kgms-1 Sin 40 = p2 / 0.117 p2 = 0.117 x sin 40 = 0.0752 kgms-1 Pythagoras : sqrt of (0.07522 + 0.08962) = 0.11697 – Agrees!!

  5. Velocities p2 = 0.0752 kgms-1 = 0.065kg x V2 V2 = p2 / 0.065 = 1.156 ms-1 =1.2 ms-1 (2 s.f) p1 = 0.0896 kgms-1 = 0.065kg x V1 V1 = p1 / 0.065 = 1.378 ms-1 =1.4 ms-1 (2 s.f)

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