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WHAT GOVERNS THE WAY THAT GASES, IN OUR ATMOSPHERE, BEHAVE?. CHARLES’ LAW. Molecules of gas at a fixed pressure and temperature , vibrate sufficiently to occupy a fixed volume. CHARLES’ LAW. Warm. CHARLES’ LAW. Increased molecular v ibration, spacing increases. Warm. CHARLES’ LAW.
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CHARLES’ LAW Molecules of gas at a fixed pressure and temperature, vibrate sufficiently to occupy a fixed volume
CHARLES’ LAW Warm
CHARLES’ LAW Increased molecular vibration, spacing increases Warm
CHARLES’ LAW Increased molecular vibration, spacing increases Warm Volume Increases
CHARLES’ LAW Increased molecular vibration, spacing increases Warm Cool Volume Increases
CHARLES’ LAW Decreased molecular vibration, spacing decreases Increased molecular vibration, spacing increases Warm Cool Volume Increases
CHARLES’ LAW Decreased molecular vibration, spacing decreases Increased molecular vibration, spacing increases Warm Cool Volume Decreases Volume Increases
CHARLES’ LAW “If the atmospheric pressure is held constant, hot gases expand to occupy a bigger volume and cold gases contract to occupy a smaller volume.” Decreased molecular vibration, spacing decreases Increased molecular vibration, spacing increases Warm Cool Volume Decreases Volume Increases
CHARLES’ LAW V=k2.T At constant Pressure Decreased molecular vibration, spacing decreases Increased molecular vibration, spacing increases Warm Cool Volume Decreases Volume Increases
CHARLES’ LAW V=k2.T At constant Pressure Decreased molecular vibration, spacing decreases Increased molecular vibration, spacing increases Warm Cool Volume Decreases Volume Increases V↓=k2.T↓ V↑=k2.T↑
BOYLE’S LAW Molecules of gas at a fixed pressure and temperature, vibrate sufficiently to occupy a fixed volume M =1.0
BOYLE’S LAW Atmospheric Pressure M =1.0 Vibrating molecules of gas
BOYLE’S LAW Compress, squeeze, add “weight” M =1.0 M = 0.5 M = 1.0
BOYLE’S LAW Decompress, relax, reduce “weight” Compress, squeeze, add “weight” M = 0.5 M =1.0 M = 0.5 M = 1.0 Increased Pressure Volume contracts Decreased Pressure Volume expands
BOYLE’S LAW “At constant temperature, the pressure exerted on a gas is inversely related to the volume the gas occupies – gases are compressible.” M = 0.5 M =1.0 M = 0.5 M = 1.0
BOYLE’S LAW P = k1/V At constant Temperature M = 0.5 M =1.0 M = 0.5 M = 1.0 P↓…. V↑ P↑ ….. V↓
HOW ARE THESE LAWS GOING TO HELP TO MOVE MASS AND ENERGY IN THE ATMOSPERIC SYSTEM?
EQUAL PRESSURE (ATMOSPHERIC) Air Filled Balloon
Lower Pressure Higher Pressure Brick Air Flow Differences in pressures cause motion of the air
Air temperature ≈ Sensible heat flux from insolation = f(latitude,season)
Changes in temperature cause changes in volume occupied by air. Air temperature ≈ Sensible heat flux from insolation = ∫ (latitude,season) V=k2.T At constant Pressure
Changes in temperature cause changes in volume occupied by air. Air temperature ≈ Sensible heat flux from insolation = ∫ (latitude,season) V=k2.T At constant Pressure P = k1/V At constant Temperature Changes in volume occupied cause changes in pressure on air
Changes in temperature cause changes in volume occupied by air. Air temperature ≈ Sensible heat flux from insolation = ∫ (latitude,season) V=k2.T At constant Pressure P = k1/V At constant Temperature Changes in volume occupied cause changes in pressure on air Differences in pressure cause movements within the atmosphere
Changes in temperature cause changes in volume occupied by air. Air temperature ≈ Sensible heat flux from insolation = ∫ (latitude,season) V=k2.T At constant Pressure Temporal and spatial differences in insolation related to pressure that moves atmosphere P = k1/V At constant Temperature Changes in volume occupied cause changes in pressure on air Differences in pressure cause movements within the atmosphere
THE EQUATION OF STATE FOR AN IDEAL GAS.PUTTING IT ALL TOGETHER!
P = R. ρ. T P = Pressure on a gas R = Gas Constant ρ = Density of gas T = Temperature of gas
P = R. ρ. T P = Pressure on a gas R = Gas Constant ρ = Density of gas T = Temperature of gas ?
P = R. ρ. T P = Pressure on a gas R = Gas Constant ρ = Density of gas: ρ = Mass/Volume T = Temperature of gas
P = R. M/V. T P = Pressure on a gas R = Gas Constant ρ = Density of gas: ρ = Mass/Volume T = Temperature of gas
P = R. M. T V Charles’ Law: Fixed P, T and V directly related 9 = 1. 1 . 2.25 0.25 If T rises to 3.0, then V must rise to 0.33 to Keep P constant at 9! 9 = 1. 1 . 3.0 0.33
P = R. M. T V Boyle’s Law: Fixed T, P and V inversely related Multiply both sides by V V . P = R. M. T Pressure declines so volume occupied increases to keep T constant 3. 3 = 1. 1. 9 4. 2.25 = 1. 1. 9
PRACTICAL APPLICATION We know that Atmospheric Pressure declines with altitude, so what can we expect to happen to Temperatures and the Density of the air as you climb a mountain or go up in an airplane? P = R. ρ. T
PRACTICAL APPLICATION We know that Atmospheric Pressure declines with altitude, so what can we expect to happen to Temperatures and the Density of the air as you climb a mountain or go up in an airplane? P = R. ρ. T Should become colder and the atmosphere “thinner”!
PRACTICAL APPLICATION We know that Atmospheric Pressure declines with altitude, so what can we expect to happen to Temperatures and the Density of the air as you climb a mountain or go up in an airplane? P = R. ρ. T Normal Lapse Rate: Rate at which temperatures decline (increase) with increase (decrease) in altitude
PRACTICAL APPLICATION We know that Atmospheric Pressure declines with altitude, so what can we expect to happen to Temperatures and the Density of the air as you climb a mountain or go up in an airplane? P = R. ρ. T Normal Lapse Rate: Rate at which temperatures decline (increase) with increase (decrease) in altitude 6.5°C per Kilometer 3.6°F per 1000 ft.
4.392 km -13°C 15°C 0 km