240 likes | 540 Views
Multiplication and Division Instructions. Module M16.4 Section 10.4. Binary Multiplication. 9 C = 156. Binary Multiplication. 13 x 12 26 13 156. 1101 1100 0000 0000 1101 1101 10011100. Hex Multiplication. Hex Multiplication. Dec. Hex. 3D
E N D
Multiplication and DivisionInstructions Module M16.4 Section 10.4
9 C = 156 Binary Multiplication 13 x 12 26 13 156 1101 1100 0000 0000 1101 1101 10011100
Hex Multiplication Dec Hex 3D x 5A 262 A x D = 82, A x 3 = 1E + 8 = 26 131 5 x D = 41, 5 x 3 = F + 4 = 13 157216 = 549010 61 x 90 5490
Hex Multiplication 0000 B0 3D MOV AL,3DH ;AL=3DH 0002 B3 5A MOV BL,5AH ;BL=5AH 0004 F6 E3 MUL BL ;AX=ALxBL product = 1572H is in AX
11 100 011 = E3 MUL BL F6 E3
16-Bit Hex Multiplication 31A4 x1B2C 253B0 4 x C = 30 A x C = 78 + 3 = 7B 1 x C = C + 7 = 13 3 x C = 24 + 1 = 25
16-Bit Hex Multiplication 31A4 x1B2C 253B0 6348 2 x 4 = 8 2 x A = 14 1 x 2 = 2 + 1 = 3 2 x 3 = 6
16-Bit Hex Multiplication 31A4 x1B2C 253B0 6348 2220C 4 x B = 2C A x B = 6E + 2 = 70 1 x B = B + 7 = 12 3 x B = 21 + 1 = 22
16-Bit Hex Multiplication 31A4 x1B2C 253B0 6348 2220C 31A4 0544D430 0000 B8 A4 31 MOV AX,31A4H ;AX=31A4H 0003 BB 2C 1B MOV BX,1B2CH ;BX=1B2CH 0006 F7 E3 MUL BX ;DX:AX = AX x BX
Unsigned Multiplication Hex Dec A5 x 24 294 14A 1734 165 x 36 990 495 5940 594010 = 173416 But A5 = 10100101 can be a signed number 2’s comp = 01011011 = 5BH = 9110 Therefore, A5 can represent -91
Signed Multiplication Dec 327610 = 0CCC16 = 0000 1100 1100 1100 2’s comp = 1111 0011 0011 0100 = F334H -91 x 36 546 273 -3276 Therefore, for signed multiplication A5H x 24H = F334H and not 1734H The 8086 IMUL instruction performs SIGNED multiplciation
Signed Multiplication 0000 B0 A5 MOV AL,A5H ;AL=A5H 0002 B3 24 MOV BL,24H ;BL=24H 0004 F6 EB IMUL BL ;AX=ALxBL product = F334H is in AX
D C 9C Binary Division 1 1 0 1 1100 10011100 1100 1 0111 1100 0 0011 0000 0110 0 1100 0000
Hex Division A C EE BC2F B28 9A F C x E = A8 C x E = A8 + A = B2
Hex Division A C EE BC2F B28 9A F 94C 63 Dividend = BC2F Divisor = EE Quotient = CA Remainder = 63 A x E = 8C A x E = 8C + 8 = 94
Hex Division A C EE BC2F B28 9A F 94C 63 0000 B8 2F BC MOV AX,0BC2FH ;AX=BC2FH 0003 B3 EE MOV BL,0EEH ;BL=EEH 0006 F6 F3 DIV BL ;AL=AX/BL quotient = AL = CAH remainder = AH = 63H
Divisor may be too small D71 rem 1 E BC2F Quotient does not fit in AL Causes a “divide by zero” interrupt
Interrupt Vector Table
Interrupt Vector Table Offset address Type number 000 004 008 00C 010 014 IP 0 1 2 3 4 5 Division by zero Single Stepping NMI Interrupt 1-Byte INT (opcode = CC) Signed overflow (INTO) Print screen CS IP CS IP CS IP CS IP CS IP CS