1 / 1

Natural constants

All problems from Physics III to VI can be solved 'by heart' by memorizing six simple numbers (correct to a few percent): c = 3 ·10 8 m/s α = 1/137 ≡ e 2 /(4 πε 0 ħc ) m = 511 keV ≈ ½ MeV/ c 2 m N = 1836 m ≈ 1 GeV/ c 2 k = 25 meV/300K. + for transition to SI-system:

mariel
Download Presentation

Natural constants

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. All problems fromPhysics III to VI can be solved 'by heart' by memorizing six simple numbers (correct to a few percent): c = 3·108 m/s α= 1/137 ≡ e2/(4πε0ħc) m = 511 keV ≈ ½ MeV/c2 mN = 1836 m ≈ 1 GeV/c2 k = 25 meV/300K + for transition to SI-system: e = 1.6·10−19 C → 1eV = 1.6·10−19 J ε0 = 107/4πc2 C/Vm μ0 = 1/ε0c2 = 4π·10−7 T/(A/m) (T = Tesla) NA = 6·1023 molecules/mole and: ħc = hc/2π ≈ 200 eV·nm (← AP) = 200 MeV·fm (← NP) = 0.2 GeV·fm (← PP) Natural constants

More Related