Chapter 6 INTEGRATION

1. Chapter 6 INTEGRATION • An overview of the area problem • The indefinite integral • Integration by substitution • The definition of area as a limit; sigma notation • The definite integral • The fundamental theorem of calculus • Evaluating definite integrals by substitution

2. 6.1 An overview of the area problem • The rectangle method for finding areas • The antiderivative method for finding areas

3. The rectangle method for finding areas • Divide the interval [a, b] into n equal subintervals, and over each subinterval • construct a rectangle that extends from the x-axis to any point on the curve y=f(x) • that is above the subinterval. • For each n, the total area of the rectangles can be viewed as an approximation to • the exact area under the curve over the interval [a, b]. If denotes the exact area • under the curve and denotes the approximation to using n rectangles, then We will call this the rectangle method for computing .

4. Figure 6.1.4 (p. 351)

5. The antiderivative method for finding areas It’s shown that if is a nonnegative continuous function on the interval [a, b], and If denotes the area under the graph of over the interval [a, x], where x is any Point in the interval [a, b], then

6. Example: For each of the function f, find the area A(x) between the graph of f and Interval [a, x]=[-2, x], and find the derivative A’(x) of this area function. (a) f(x)=3 (b) f(x)=x+2 (3) f(x)=2x+5 Solution (a): From figure, we see A(x)=3(x-(-2))=3(x+2)=3x+3 is the area of a rectangle of height 3 and base x+2. For this area function A’(x) = 3 = f(x)

7. Example: For each of the function f, find the area A(x) between the graph of f and Interval [a, x]=[-2, x], and find the derivative A’(x) of this area function. (a) f(x)=3 (b) f(x)=x+2 (3) f(x)=2x+5 Solution (b): From figure, we see is the area of an isosceles right triangle with base and height equal to x+1. For this area function, A’(x) = x+2 = f(x).

8. Example: For each of the function f, find the area A(x) between the graph of f and Interval [a, x]=[-2, x], and find the derivative A’(x) of this area function. (a) f(x)=3 (b) f(x)=x+2 (3) f(x)=2x+5 Solution (c): From figure, we see is the area of a trapezoid with parallel sides of length 1 and 2x+5 and with altitude x-(-2)=x+2. For this area function, A’(x) = 2x+5 = f(x).

9. Two Methods Compared • The antiderivative method is usually the more efficient way to compute areas; • The rectangle method is used to formally define the notion of area, thereby allow • us to prove mathematical results about areas.

10. 6.2 The indefinite integral For example: are all antiderivatives of In fact: THEOREM: If F(x) is any antiderivatve of f(x) on an interval I, then for any constant C the function F(x)+C is also an antiderivative on that interval. Moreover, each Antiderivative of f(x) on the interval I can be expressed in the form F(x)+C by choosing The constant C appropriately.

11. The process of finding antiderivatives is called antidifferentiation or integration. Thus, if , then it can be recast using integral notations . where C is understood to represent an arbitrary constant. Note: is called an indefinite integral. Is called an integral sign, the function f(x) is called the integrand, and the constant C is called the constant of integration.

12. dx in serves to identify the independent variable. If it is different from x, then the notation must be adjusted appropriately. Thus, are equivalent statements. For example: Note:

13. Integration Formulas

14. Example:

15. Properties of the indefinite integral

16. The statements in Theorem 6.2.3 can be summarized by the following formulas:

17. Example: Evaluate (a) (b) Solution (a): Solution (b):

18. Example: (a) (b) Solution (a): Solution (b):