1 / 3

-Calculations and results:-

mary-gilmore
Download Presentation

-Calculations and results:-

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Exp#7:- principle of Archimedes_Idea:- The body submerged in a liquid removes the size of the liquid equal to the size of the bode. _Elements:-A small metal ball –Water-Balance-Glycerin. -Steps:- -Weigh the weight of the ball in the air and a weight of M.-Weigh the weight of the ball in the water and to be m.-Weigh the weight of the ball in another liquid such as glycerin and to be m1. -find mass of water displaced from the relationship V=M-m-Find mass of glycerin displaced from the relationship V=M1-m-To find a specific density using the relationship M/M-m -Specific gravity Allgelsrin M-m1/M-m

  2. -Calculations and results:- • -weight the ball in the air =M=35g. • -Weight the ball in the water =m=31g. • -weight the ball in the glycerin =m1=30g. • Mass of water displacement =mass the ball in the air – mass in the mater • =M-m • =4g. • Cluster quality of iron=M/M-m =35/35-31 =8.7 • Cluster quality of glycerin=M-m1/M-m =35-30/35-31=1.2

  3. -Conclusion:- lada immersion in a liquid the body weight decreased by weight of the liquid was displaced. No he lada body immersion in a liquid it is strongly in fluenced by the payment of this topic to the top and Force is equal to the weight of fluid displacement.

More Related