210 likes | 313 Views
A 10kg wooden box is placed on a wooden inclined plane that forms an angle of 37 degrees with the horizontal. Will the box stay at rest or accelerate?. 10kg. 37 ˚. F W =100N. 37 ˚. F N =?. F W =100N. 37 ˚. F N =?. 37 ˚. F perpendicular =F W ·cos( 37 ˚). F W =100N.
E N D
A 10kg wooden box is placed on a wooden inclined plane that forms an angle of 37 degrees with the horizontal. Will the box stay at rest or accelerate? 10kg 37˚
FW=100N 37˚
FN=? FW=100N 37˚
FN=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=? Ffriction=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=? Fperpendicular=FW ·cos(37˚) Ffriction=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=? Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚) Ffriction=? 37˚ Fperpendicular=FW ·cos(37˚) FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=? Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=? Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? Fparallel=FW ·sin(37˚) 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? Fparallel=FW ·sin(37˚) Fparallel=100N·sin(37˚) 37˚ Fperpendicular=80N FW=100N Fparallel=FW ·sin(37˚) 37˚
FN=80N Fperpendicular=FW ·cos(37˚) Fperpendicular=100N·cos(37˚)=80N FN=Fperpendicular=80N Ffriction=? Fparallel=FW ·sin(37˚) Fparallel=100N·sin(37˚)=60N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚
FN=80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚
FN=80N Ffriction=μ· FN Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚
FN=80N Ffriction=μ· FN Ffriction= 0.42· 80N Ffriction=? 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚
FN=80N Ffriction=μ· FN Ffriction= 0.42· 80N=34N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚
FN=80N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚
FN=80N Fnet=Fparallel-Ffriction Fnet=60N-34N=26N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚
FN=80N Fnet=Fparallel-Ffriction Fnet=60N-34N=26N Ffriction=34N 37˚ Fperpendicular=80N FW=100N Fparallel=60N 37˚