120 likes | 196 Views
Stoichiometry. By Luke Sayers. Stoichiometry. What is the mass of all the chemicals in a reaction between Potassium Hydroxide and Aluminum when 4.18g of Aluminum is used?. 1.Write a complete and balanced chemical equation. 3K(OH) + Al --> Al(OH) 3 + 3K.
E N D
Stoichiometry By Luke Sayers
Stoichiometry What is the mass of all the chemicals in a reaction between Potassium Hydroxide and Aluminum when 4.18g of Aluminum is used?
1.Write a complete and balanced chemical equation 3K(OH) + Al --> Al(OH)3 + 3K
2.Draw a column for each chemical 3K(OH) + Al --> Al(OH)3 + 3K
3. Write the amount of given in the appropriate column 3K(OH) + Al --> Al(OH)3 + 3K 4.18g
4.Convert the amount given into moles 3K(OH) + Al --> Al(OH)3 + 3K 4.18g 4.18g/1 x 1/26.981= .115mol
5.Find moles for each other chemicala) In each of the other columns write the moles of given (x) a fraction 3K(OH) + Al --> Al(OH)3 + 3K .115mol x 4.18g .115mol x .115mol x 4.18g/1 x 1/26.981= .115mol
5.Find moles for each other chemicalb) The numerator of the fraction is the coefficient of that column 3K(OH) + Al --> Al(OH)3 + 3K .115mol x 3/ 4.18g .115mol x 1/ .115mol x 3/ 4.18g/1 x 1/26.981= .115mol
5.Find moles for each other chemicalc) The denominator of the fraction is the coefficient of the given column 3K(OH) + Al --> Al(OH)3 + 3K .115mol x 3/1= 4.18g .115mol x 1/1= .115mol x 3/1= 4.18g/1 x 1/26.981= .115mol
5.Find moles for each other chemicald) Do the math and label as moles 3K(OH) + Al --> Al(OH)3 + 3K .115mol x 3/1= 4.18g .115mol x 1/1= .115mol x 3/1= .465mol 4.18g/1 x 1/26.981= .115mol .465mol .115mol
6.Convert all moles into grams 3K(OH) + Al --> Al(OH)3 + 3K .115mol x 3/1= 4.18g .115mol x 1/1= .115mol x 3/1= .465mol x 4.18g/1 x 1/26.981= .115mol x .465mol x 56.1056g/1 = .115mol 78.0034g/1 = 39.0983g/1 = 26.1g 12.1g 18.2g
7.Verify the Law of Conservation of mass 3K(OH) + Al --> Al(OH)3 + 3K .115mol x 3/1= 4.18g .115mol x 1/1= .115mol x 3/1= .465mol x 4.18g/1 x 1/26.981= .115mol x .465mol x 56.1056g/1 = .115mol 78.0034g/1 = 39.0983g/1 = 26.1g 12.1g 18.2g 26.1g+4.18g=30.3g 12.1g+18.2g=30.3g