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Investigation: Ohms Law Resistances in Series and Parallel. Created for CVCA Physics By Dick Heckathorn 26 March 2K + 4. Finding Equivalent Resistance. 1. Measure and record the resistance of three like resistors. R 1. R 3. R 2.
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Investigation:Ohms LawResistances in Seriesand Parallel Created for CVCA Physics By Dick Heckathorn 26 March 2K + 4
1. Measure and record the resistance of three like resistors. R1 R3 R2
2. Connect two of the resistors end to end (in series) and measure the resistance across any two. R1 R2 R1 R3 R2 R3
3. Can you develop a rule from which you can predict the equivalent resistance of two resistors in series. R1 R2 R1 R3 R2 R3
4. Connect all three resistors end to end (in series) and measure the resistance across all three. R1 R2 R3 • 5. Does your rule hold for three resistors connected in series?
6. Repeat the measurements first using two and then all resistors each of a different value. R1 R2 R3 • 7. Does your rule hold for three different resistors connected in series?
1. Measure and record the resistance of three like resistors R3 R1 R2
2. Connect two of the resistors as shown (in series) and measure the resistance across each end. R2 R1 R3 R2 R3 R1
3. Can you develop a rule from which can predict the equivalent resistance of two resistors in parallel? R3 R2 R3 R1 R2 R1
4. Connect all three resistors as shown (in parallel) and measure the resistance across all three. R3 R2 R1 • 5. Does your rule hold for three resistors connected in parallel?
6. Repeat the measurements first using two and then all resistors each of a different value. R2 R1 R3 R2 R1 • 7. Does your rule hold for three different resistors connected in series?
Set up the following circuit Why is the bulb as bright as it is?
A Set up the following circuit
A VR VB Measure and record: I R Resistance R Voltage VR Current I Voltage VB
A VR VB Conclusion(s) I R I? V,I,andR? VRand VB? Power = ?
Resistance in Series • 1. Current (I) in the circuit is everywhere the same. • 2. Potential difference (VB) supplied by the battery equals the potential difference (VR) lost in the component connected to the battery.
Set up the following circuit Why are the bulbs as bright as they are?
A Set up the following circuit
A VB V1 V2 Measure and record: I R1 R2 Current I Resistance R1 Voltage V1 Voltage V2 Resistance R2 Voltage VB
A VB V1 V2 Conclusion(s) I R1 R2 I? V,I,andR? V1, V2and VB?
Resistance in Series • 1. Current (I) in the circuit is everywhere the same. • 2. Potential difference (VB) supplied by the battery equals the sum of the potential difference (V1+V2) lost in the components connected in series.
Set up the following circuit Why are the bulbs as bright as they are?
A A1 A2 Set up the following circuit
A A1 VB V2 V1 A2 Measure and record: I I2 I1 R1 R2 Current I2 Current I1 Current I Resistance R1 Resistance R2 Voltage V1 Voltage V2 Voltage VB
A A1 VB V2 V1 A2 Conclusion(s) I I2 I1 R1 R2 I? V,I,andR? V1, V2and VB?
Resistance Parallel • 1. Current (I) from the battery equals the sum of the currents (I1+ I2) through the separate resistances. • 2. Potential difference (VB) supplied by the battery equals the the potential difference (V1 = V2) lost in the resistances connected in parallel.
Summary Why is the bulb as bright as it is?
Summary Why are the bulbs as bright as they are?
Summary Why are the bulbs as bright as they are?