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AREA OF COMPOSITE FIGURES. COMPOSITE FIGURES. A composite figur e is made of triangles, quadrilaterals, semicircles, and other 2-D figures. A semicircle is half of a circle. Examples:. TRIANGLE. RECTANGLE. SEMICIRCLE. TRAPEZOID.
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COMPOSITE FIGURES • A composite figure is made of triangles, quadrilaterals, semicircles, and other 2-D figures. • A semicircleis half of a circle. • Examples: TRIANGLE RECTANGLE SEMICIRCLE TRAPEZOID To find the area of a composite figure, separate it into figures with areas you know how to find. Then add those areas.
AREA OF COMPOSITE FIGURES • Let’s find the area of the following composite figure. 6 cm This figure can be separated into a rectangle and a semicircle. Now we just find the area of each figure. 3 cm 14 cm AREA OF SEMICIRCLE: A = r2(this is area of a 2 circle, cut in ½) A = 3.14 4 4 2 A = 50.24 = 25.12 cm2 2 AREA OF RECTANGLE: A = lw A = 14 3 A = 42 cm2 BOTH AREAS ADDED TOGETHER: 42 + 25.12 = 67.12 cm2
AREA OF COMPOSITE FIGURES • Now you try to find the area of the following composite figure. This figure can be separated into a triangle and ¾ of a circle. Now we just find the area of each figure. 3 cm Together: 18 + 21.195 = 39.195 cm2 for the area of the composite figure. 12 cm AREA OF CIRCLE: A = r2(this is area of a WHOLE circle) A = 3.14 3 3 A = 28.26 cm2 (WHOLE CIRCLE) Now, we only need area for 3 parts of the circle ; so we need to divide the area by 4 to get ¼ then multiply by 3 to get ¾. 28.26 ÷ 4 = 7.065. 7.065 3 = 21.195 cm2 is ¾ of circle. AREA OF TRIANGLE: A = bh 2 A = 12 3 2 A = 36 = 18 cm2 2
AREA OF COMPOSITE FIGURES • Now you try again to find the area of the following composite figure. This figure can be separated into a square & a rectangle. Now we just find the area of each figure. 9 cm 6 cm 3 cm 12 cm AREA OF SQUARE: A = side side A = 3 3 A = 9 cm2 AREA OF RECTANGLE: A = bh A = 12 3 A = 36 cm2 Together: 9 + 36 = 45 cm2 for the area of the composite figure.
AREA OF SHADED PARTS OF FIGURES • Sometimes you have to find the area of the shaded region in each figure. • This figure is a large circle with a small circle inside it. • To find the area of just the shaded part (the outer circular part), • we need to find the area of both the larger circle and the smaller • white filled circle, and then subtract the two areas to get just the shaded circle’s area. 6 m 8 m AREA OF SMALL CIRCLE: A = r2 A = 3.14 3 3 A = 28.26 m2 AREA OF LARGE CIRCLE: A = r2 A = 3.14 4 4 A = 50.24 m2 Now, we take the 2 areas and subtract: 50.24 – 28.26 = 21.98 m2
AREA OF SHADED PARTS OF FIGURES • Now you try • This figure is a large circle inside a square. • Find the area of only the rectangle part showing around the circle. 6 m 12 m AREA OF SQUARE: A = s2 A = 12 12 A = 144 m2 AREA OF CIRCLE: A = r2 A = 3.14 6 6 A = 113.04 m2 Now, we take the 2 areas and subtract: 144.00 – 113.04 = 30.96 m2